Easy
ok, so
for y=a(x-h)^2+k
the vertex is (h,k)
given that the the vertex is (-2,-20)
y=a(x-(-2))^2+(-20)
y=a(x+2)^2-20
find a
when x=0, then y=-12
-12=a(0+2)^2-20
-12=a(2)^2-20
8=4a
2=a
equation is
y=2(x+2)^2-20
if the last term is positive, then maybe y=2(x+2)^2+(-20)?
unless you typed something wrong, then you are right that the last term is -20
Slope is 0.5
I hope it helps for more info pls msg me
Umm isn’t there more context to this question? I rlly can’t help if you don’t add more detail
The nurse should administer to the patient H. 487.5 miligrams
Answer:
Its A
Step-by-step explanation:
The answer is A, because the dot means it cant be 11, which is what the question is asking. Hope this helps!
