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Norma-Jean [14]

3 years ago

11

If

^2=ax^2+bx+c" align="absmiddle" class="latex-formula">, what is the value of a+b+c?

2 answers:

Vinvika [58]3 years ago

4 0

Answer:

64

Step-by-step explanation:

(3x+5)^2 = ax^2 +bx+c

FOIL the left side

(3x+5) (3x+5)

9x^2 +15x+15x+25

Combine like terms

9x^2 +30x+25

a=9

b= 30

c= 25

a+b+c = 9+30+25 = 64

enyata [817]3 years ago

3 0

Answer:

64

Step-by-step explanation:

(3x + 5)² = ax² + bx + c

9x² + 30x + 25 = ax² + bx + c

a = 9

b = 30

c = 25

a + b + c

9 + 30 + 25

64

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Write a rule for the nth term of the geometric sequence for which a1=−6 and a5=−486

patriot [66]

The geometric rule for the nth term of the geometric sequence for which a1 =−6 and a5=−486 is -6 × 3^(n - 1)

<h3>The nth term of a geometric sequence</h3>

First term, a1 = -6

Fifth term, a5 = -486

a5 = ar^(n - 1)

-486 = -6 × r^(5-1)

-486 = -6r⁴

r⁴ = -486 / 6

r⁴ = 81

r = 4√81

r = 3

Geometric rule:

nth term = ar^(n-1)

nth term = -6 × 3^(n - 1)

Learn more about geometric sequence:

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7 0

2 years ago

Your the best if you could help

Andre45 [30]

Answer:

see below

Step-by-step explanation:

1. a = 18, 2. n = -19, 3. x = -17, 4. v = -6, 5. a = 9, 6. x = -2, 7. k = -4, 8. m = -19

9. n = 3, 10. a = -7, 11. n = -5, 12. n = -6, 13. x = -1/3, 14. m = 2/3 15. m = -9.8

16. n = 7.9, 17. x = 0, 18. b = 2, 19. v = -8, 20. b = -4, 21. n = 3, 22. p = 3.3

4 0

3 years ago

A man bought a bicycle for $400 and sold it at a loss of 35%. How much did he lose?

Vlad [161]

The answer should be 140, I hope this helps! Have a fantastic day!!

8 0

3 years ago

Read 2 more answers

2. Find the product of each of the following:

Kruka [31]

Step-by-step explanation:

$i) \: \frac{3}{5} \times ( \frac{ - 7}{8} ) = - \frac{21}{40} \\ \\ ii) \: \frac{ - 9}{2} \times \frac{5}{4} = - \frac{45}{8} \\ \\ iii) \: \frac{ - 6}{11} \times \frac{5}{3} = - \frac{10}{11} \\ \\ iv) \: \frac{ - 2}{3} \times \frac{6}{7} = - \frac{4}{7} \\$

6 0

3 years ago

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

3 years ago