Answer:
A, B and E could not be probabilities
Step-by-step explanation:
By definition, <u>a probability could be any number between 0 and 1. </u>So a probability P would be 0≤P≤1. In percentages, 0% ≤ P ≤ 100%
Considering this we would have that:
A) 110% could not be a probability because it's larger than 100%
B) 5.42 could not be a probability because it's larger than 1.
C) 0.001 could be a probability because it's larger than 0 and smaller than 1 (It doesn't matter how small it is)
D) 0.58 could be a probability because it's between 0 and 1.
E) -120% could not be a probability because it's smaller than zero. (it's a negative number)
Thus, A), B) and E) could not be probabilities.
Answer:
183 times 1.04=190.32
Step-by-step explanation:
Answer:
The correct answer is B. 20%
Step-by-step explanation:
Have a great day <3
Answer:
29/6
Step-by-step explanation:
The expression that we have to evaluate in this problem is

for
.
First of all, we re-arrange the expression. We know that:
- The product of a positive number (+) and a negative number (-) is negative (-)
- The product of a negative number (-) and a negative number (-) is positive (+)
So we can rewrite the expression as

Also, we can combine the two numerical terms:

Therefore the expression becomes

Now we can substitute
, and we find:
