The car has slowed down because of the deceleration or decelerating force acting on it. The decelerating force acting on it is generated by the application of brakes or the frictional force acting in the opposite direction of car's motion.
The answer is B. Hope I helped!
Answer:
d)
Explanation:
Newton's 3rd Law tells us that for every action we will have a reaction equal in magnitude and opposite in direction. In a collision between obects A and B this means that the force on A applied by B will be equal in magnitude than the force on B applied by A, which leaves d as the true answer and the rest as false.
Answer: The combined velocity = 0.413m/a
Maximum angle Ø = 54.7
Explanation: Please find the attached files for the solution
Answer:
a) F = (137.4 i ^ + 185 j ^) N
b) F = 230.2 N , θ = 53.5º
Explanation:
In this exercise we ask to find the net force, for which we will define a coordinate system fix the donkey and use trigonometry to decompose the forces
Jack F₁ₓ = 63.9 N
Jill F₂ = 79.1 N with direction 45º to the left
cos (180 -45) = F₂ₓ / F₂
sin 135 =
/ F₂
F₂ₓ = F₂ cos 135
F_{2y} = F₂ sin 135
F₂ₓ = 79.1 cos 135 = -55.9 N
F_{2y} = 79.1 sin 135 = 55.9 N
Jane F₃ = 183 N direction 45th to the right
cos 45 = F₃ₓ / F3
sin 45 = F_{3y} / F3
F₃ₓ = F₃ cos 45 = 183 cos 45
F_{₃y} = F₃ sin 45 = 183 sin 45
F₃ₓ = 129.4 N
F_{3y} = 129.4 N
we add each component of the force
Fₓ = F₁ₓ + F₂ₓ + F₃ₓ
Fₓ = 63.9 + (-55.9) + 129.4
Fₓ = 137.4 N
F_{y} = F_{2y} + F_{3y}
F_{2y} = 55.9 + 129.4
F_{2y} = 185.3 N
we can give the result of the forms
a) F = (137.4 i ^ + 185 j ^) N
b) in the form of module and angle
F = RA (Fₓ² + F_{y}²)
F = Ra (137² + 185²)
F = 230.2 N
tan θ = F_{y} / Fₓ
θ = tan⁻¹ F_{y} / Fₓ
θ = tan⁻¹ (185/137)
θ = 53.5º