Answer:
(d) I and III
Explanation:
Motion of the 1st light ball
I. Since the heavier starts with an initial velocity v0, and both balls end up traveling the same distance s. From the 2 motion equation above we can conclude that their time must be different
II. Both balls are affected by the same gravitational acceleration g
III. Velocity before the impact of the light ball
And the heavy ball
Since they have the same acceleration g and distance s. But the heavy ball has an initial push. It would end up with a larger speed.
Answer:
Answer: The spring constant of the spring is k = 800 N/m, and the potential energy is U = 196 J. To find the distance, rearrange the equation: The equation to find the distance the spring has been compressed is therefore: The spring has been compressed 0.70 m, which resulted in an elastic potential energy of U = 196 J being stored.
Explanation:
Answer:
1.) Waves carry energy through empty space or through a medium without transporting matter. While all waves can transmit energy through a medium, certain waves can also transmit energy through empty space. ... When waves travel through a medium, the particles of the medium are not carried along with the wave.
2.) Mechanical Waves are waves which propagate through a material medium (solid, liquid, or gas) at a wave speed which depends on the elastic and inertial properties of that medium. There are two basic types of wave motion for mechanical waves: longitudinal waves and transverse waves. Longitudinal waves vibrating in the direction of propagation while Transverse waves vibrate at right angles to the direction of its propagation.
3.) They can carry a little energy or a lot of energy. They can be transverse or longitudinal. However, all waves have common properties—amplitude, wavelength, frequency, and speed. Amplitude describes how far the medium in a wave moves.
I hope this helps!
Answer:
Car travel a distance of 60.06 m in 6 sec
Explanation:
We have given initial velocity v = 20 m/sec
Time = 6 sec
As the car stops finally so final velocity v = 0
From the first equation of motion
v = u+at (as the car velocity is slows down means it is a case of deceleration)
So v = u-at
Now from second equation of motion 
By conservation of momentum, the initial recoil speed of the
rifle is:
u = 904kg * 0.0106 kg / 3.53 kg = 2.7146 m/s
The final recoil speed v is zero in a distance of d = 0.0346 m
So the rifle's acceleration is a = (0 - u^2) / 2*d = -2.7146^2 / 2*.0323
m/s^2
a = -114.07m/s^2
