F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
5x+2y =-6 ........1
3x-2y = 22 ........2
Add both Equations
we get
8x = 16
Divide both sides by 8
x = 2
Substitute x = 2 into any of the equations
3(2) - 2y = 22
-2y = 22 - 6
- 2y = 18
Divide both sides by -2
y = - 9
x = 2 y = - 9
Hope this helps
Answer:
102°
Step-by-step explanation:
As the vertically opposite angles are equal,

Now let's solve for x now






Now let's find the value of KNL

Hope this helps you.
Let me know if you have any other questions ;-)
I pretty sure the best answer would be f(x)=cbrt(27-x)
cbrt means cube root by the way.
Answer:
The smaller number is 0.6666... repeating, and the larger number is 1.3333... repeating.
Step-by-step explanation: