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3 years ago

How do you solve this system: y= -3/2x, and 3x+2y=-4 by substitution?

Mathematics

2 answers:

crimeas [40]3 years ago

7 0

Plug in equation for y into second equation: 3x+2(-3/2x)=-4

Soloha48 [4]3 years ago

4 0

Download Photomath it will answer it with step by step work

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140 subtracted from the square of a number the result is three times the number find the negative solution

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Answer:

$Suppose~that~the~number~is~x.\\According~to~question,\\x^2-140=3x\\or, x^2-3x-140=0\\From~the~quadratic~formula,\\x = \frac{-(-3)+\sqrt{(-3)^2-4(1)(-140)} }{2(1)} ~and ~x= \frac{-(-3)-\sqrt{(-3)^2-4(1)(-140)} }{2(1)} \\or, x = \frac{3+\sqrt{9+560} }{2}~and~x=\frac{3-\sqrt{9+569} }{2}\\or, x = \frac{3+\sqrt{569} }{2}~and~x=\frac{3-\sqrt{569} }{2}\\So,~the~required~negative~number~is~\frac{3-\sqrt{569} }{2}.$

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You saved $300 to spend over the summer. You decide to budget $50 to

Naya [18.7K]

Answer:

Step-by-step explanation:

part A:

okay so you saved $300 and choose to spend $50 a week

the 300 is positive and is the y-intercept since thats the amount of money you start with

and the 50 is negative because that is being spent and is the slope

so the equation is:

y = -50x + 300

part B:

the graph will be on the bottom

the (6, 0), aka the x-intercept, shows that in 6 weeks you will be out of money

the (0, 300), aka the y-intercept, shows that in the beginning of summer you have $300

part C:

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