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andrew11 [14]
4 years ago
14

The largest ship in Christopher Columbus' "fleet" was the Santa Maria, which displaced about 100 tons (1 ton = 2,000 pounds) of

seawater when fully loaded. Assuming the average density of seawater surrounding the ship was 1.024 g mL-1, calculate the total volume of seawater (in m3) displaced by the ship's hull.
Chemistry
1 answer:
Neporo4naja [7]4 years ago
7 0

Answer:

V=97.7m^3

Explanation:

Hello,

In this case, considering that the density is defined in terms of mass and volume as follows:

\rho =\frac{m}{V}

Due to the fact that 100 tons of water were displaced, whose value in grams is:

m=100tons*\frac{1000kg}{1ton} *\frac{1000g}{1kg}=1x10^8g

Thus the displaced volume in cubic meters was:

V=\frac{m}{\rho}=\frac{1x10^8g}{1.024g/mL}  =97656250mL\\\\V=97656250mL*\frac{1L}{1000mL}*\frac{1m^3}{1000L}\\  \\V=97.7m^3

Regards.

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       = constant

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The mole fraction of oxygen at a location far from pellet is 1.

Thus, separating the variables and integrating result into  the following:

W_{P}\int_{R}^{\infty} \frac{dr}{r^{2}}=-4\pi

r^{2}cD_{PQ}\int_{y_{P,R}}^{y_{P,\infty }}dy_{P}

-W_{P}\frac{1}{r}\mid ^{\infty }_{R}= -4\pi cD_{PQ}(y_{P,\infty }-y_{P,R})

=> W_{P}= - 4\pi cD_{PQ}(1-y_{P,R})R

The mole of oxygen arrived at the carbon surface is equal to the mole of oxygen consumed by the chemical reaction.

W_{P} = 4 \pi R^2R"

W_{P}= 4\pi R^{2}k_{1}"C_{O_{2}}\mid _{R}

W_{P}= 4\pi R^{2}k_{1}"c y _{P,R}

-4\pi cD_{PQ}(1-y_{P,R})R= - 4\pi R^{2}k_{1}"c y _{P,R}

y_{P,R}=\frac{D_{PQ}}{D_{PQ}+Rk_{1}}

y_{P,R}=\frac{1.7 \times 10^{-4}}{1.7\times 10^{-4}+10^{-3}\times 0.1}

\mathbf{= 0.631}

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W_{P}= - 6.66\times 10^{-9}kmol/s

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