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vovikov84 [41]
3 years ago
14

Based on graph 4 across a period the electronegativity​

Chemistry
2 answers:
Romashka-Z-Leto [24]3 years ago
7 0
4


Answer with explanation
viva [34]3 years ago
3 0
Can you please type the question here?
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Convert each of the potentials. The silver–silver chloride and calomel reference electrodes are saturated with resulting in cell
gogolik [260]

Answer:

-0.044 V

Explanation:

The overall electrode potential is usually estimated by subtracting the potential of the reference electrode from the potential of the system in question. In the given problem, the standard electrode potential of silver-silver chloride with respect to the standard hydrogen electrode is +0.197 V. In addition, the potential of the calomel reference electrode with respect to the standard hydrogen electrode is +0.241 V. Using the data above, the potential of with respect to silver-silver chloride is equivalent to 0.197-0.241 = -0.044 V.

8 0
3 years ago
"A solution with a total volume of 850.0 mL contains 43.5 g Mg(NO3)2. If you remove 25.0 mL of this solution and then dilute thi
ycow [4]

Answer: C = 0.014M

Explanation:

From n= m/M= CV

m =43.5 M= 148, V=850ml

43.5/148= C× 0.85

C= 0.35M

Applying dilution formula

C1V1=C2V2

C1= 0.35, V1= 25ml, C2=?, V2= 600ml

0.35× 25 = C2× 600

C2= 0.014M

7 0
4 years ago
How many atoms are there in 2.3 grams of zirconiumn?
Effectus [21]

Answer:

1.51834×10^22

Explanation:

Number of atom=Mass/Molar Mass × avogadros constant

2.3g/91.224g/mol × 6.203×10^23

5 0
3 years ago
What is the density of CHCL3 vapor at 1.00atm and 298K?
Advocard [28]

Answer:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

Explanation:

By ideal gas equation:

PV=nRT

Number of moles (n)

can be written as: n=\frac{m}{M}

where, m = given mass

M = molar mass

PV=\frac{m}{M}RT\\\\PM=\frac{m}{V}RT

where,

\frac{m}{V}=d which is known as density of the gas

The relation becomes:

PM=dRT    .....(1)

We are given:

M = molar mass of chloroform= 119.5 g/mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the gas = 298K

P = pressure of the gas = 1.00 atm

Putting values in equation 1, we get:

1.00atm\times 119.5g/mol=d\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\d=4.88g/L

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

7 0
3 years ago
Describe how surface currents would be effective Earth did not rotate
kicyunya [14]
The moon is what makes currents so if there was no moon there would be no current in our oceans. The way it makes currents is from the gravitational pull.
Brainliest? :)
3 0
3 years ago
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