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IgorC [24]
3 years ago
14

A sample of chlorine gas fills a vessel at a temperature of 37oC. The vessel has a volume of 3L and experiences a pressure of 3a

tm. What is the mass of the chlorine gas in the vessel
Chemistry
1 answer:
Iteru [2.4K]3 years ago
7 0

Answer:

25.1 g is the mass of chlorine in the sample

Explanation:

P . V = n . R . T

We apply the Ideal Gases Law to solve the excersise.

We need to convert the T°C to T°K → 37°C + 273 = 310K

We replace data: 3 atm . 3L = n . 0.082 L.atm /mol.K . 310K

9 atm.L / (0.082 L.atm /mol.K . 310K) = n → 0.354 moles

We convert the moles to mass, to reach the answer

0.345 mol . 70.9g / 1mol = 25.1 g

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ASHA 777 [7]

Answer:

For enlightenment, development and making people understand the usefulness of the product

6 0
2 years ago
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Given: 36.7 grams of CaF2 is added to 300 mL water. Find molarity?
BigorU [14]
<h3>Answer:</h3>

2 M

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Unit 0</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution
<h3>Explanation:</h3>

<u>Step 1: Define</u>

36.7 g CaF₂

300 mL H₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of Ca - 40.08 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of CaF₂ - 40.08 + 2(19.00) = 78.08 g/mol

1000 mL = 1 L

<u>Step 3: Convert</u>

<em>Solute</em>

  1. Set up:                               \displaystyle 36.7 \ g \ CaF_2(\frac{1 \ mol \ CaF_2}{78.08 \ g \ CaF_2})
  2. Multiply:                             \displaystyle 0.470031 \ mol \ CaF_2

<em>Solution</em>

  1. Set up:                              \displaystyle 300 \ mL \ H_2O(\frac{1 \ L \ H_2O}{1000 \ mL \ H_2O})
  2. Multiply:                            \displaystyle 0.3 \ L \ H_2O

<u>Step 4: Find Molarity</u>

  1. Substitute [M]:                    \displaystyle x \ M = \frac{0.470031 \ mol \ CaF_2}{.3 \ L \ H_2O}
  2. Divide:                                \displaystyle x = 1.56677 \ M

<u>Step 5: Check</u>

<em>Follow sig fig rules and round.</em> <em>We are given 1 sig fig as our lowest.</em>

1.56677 M ≈ 2 M

8 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.71 g of ethane is
DanielleElmas [232]

Answer:

6g

Explanation:

Step 1:

The balanced equation for the reaction between gaseous ethane and gaseous oxygen. This is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Step 2:

Determination of the masses of C2H6 and O2 that reacted and the mass of CO2 produced from the balanced equation. This is illustrated below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

Mass of C2H6 from the balanced equation = 2 x 30 = 60g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 7 x 32 = 224g

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 4 x 44 = 176g

From the balanced equation above,

60g of C2H6 reacted with 224g of O2 to produce 176g of CO2.

Step 3:

Determination of the limiting reactant.

We need to determine the limiting reactant as it will be needed to obtain the maximum mass of CO2.

From the balanced equation above,

60g of C2H6 reacted with 224g of O2.

Therefore, 2.71g of C2H6 will react with = (2.71 x 224)/60 = 10.12g of O2.

From the above calculation, we can see that a higher mass of O2 is needed to react with 2.71g of C2H6, therefore, O2 is the limiting reactant.

Step 4:

Determination of the maximum mass of CO2 produced when 2.71 g of ethane is mixed with 7.6 g of oxygen.

The limiting reactant is used to determine the maximum mass.

From the balanced equation above,

224g of O2 produce 176g of CO2.

Therefore, 7.6g of O2 will produce = (7.6 x 176)/224 = 5.97g ≈ 6g of CO2

From the calculations made above, the maximum mass of CO2 produced is 5.97 ≈ 6g

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4 years ago
Put the rules in order, first rule up top.
ValentinkaMS [17]

Answer:

  • Write down the elements
  • Balance Metals
  • Balance Non- metals
  • Balance Oxygen
  • Balance Hydrogen.

3 0
3 years ago
The diagram shows different forms of thermal energy transfer.
Kaylis [27]

Answer:

Conduction

Explanation:

The handle is touching the pot.

And I got it wrong

4 0
3 years ago
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