Answer:
91/216
Step-by-step explanation:
The probability of getting a 4 in the first three rolls is 1 minus the probability of not getting a 4 on any of the rolls.
P(at least one 4) = 1 − P(no 4s)
P(at least one 4) = 1 − (5/6)³
P(at least one 4) = 91/216
Alternatively, you can calculate it this way.
The probability of getting a 4 on the first roll is 1/6.
The probability of getting a 4 on the second roll is (5/6) (1/6) = 5/36.
The probability of getting a 4 on the third roll is (5/6) (5/6) (1/6) = 25/216.
The probability of any of the three events is 1/6 + 5/36 + 25/216 = 91/216.
I think both answers are C.
(-8,-4) and (-5,-2)
other one
Fix the compass at points P and T
24 cubes can filled up the prism
Solution:
The image of the question is attached below.
Given data:
Length of the prism = 2 cm
Breadth of the prism = 1 cm
Height of the prism = 
cm
Volume of the prism = length × breadth × height
cubic cm
Volume of the prism = 3 cubic cm
Side length of the cube = 
cm
Volume of the cube = side × side × side
cubic cm
Volume of the cube = 
cm
Number of cubes = 24
Hence 24 cubes can filled up the prism.
Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.
Answer:
the last one
Step-by-step explanation:
Two lines will be parallel when their slopes are equal, and two lines will be perpendicular when their slopes are negative reciprocals of each other. Our slopes for these two equations are the coefficient for the x value. Both slopes are equal so these lines are parallel.
