Multply across the fraction so
1/2 * 3/4= (1*3)/(2*4)=3\8
Answer:
(4/3, 7/3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations of using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
7x - y = 7
x + 2y = 6
<u>Step 2: Rewrite Systems</u>
Equation: x + 2y = 6
- [Subtraction Property of Equality] Subtract 2y on both sides: x = 6 - 2y
<u>Step 3: Redefine Systems</u>
7x - y = 7
x = 6 - 2y
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 7(6 - 2y) - y = 7
- Distribute 7: 42 - 14y - y = 7
- Combine like terms: 42 - 15y = 7
- [Subtraction Property of Equality] Subtract 42 on both sides: -15y = -35
- [Division Property of Equality] Divide -15 on both sides: y = 7/3
<u>Step 5: Solve for </u><em><u>x</u></em>
- Define original equation: x + 2y = 6
- Substitute in <em>y</em>: x + 2(7/3) = 6
- Multiply: x + 14/3 = 6
- [Subtraction Property of Equality] Subtract 14/3 on both sides: x = 4/3
To find the gradient of a line we first hv to find the formula
so Gradient=√X1-x2and √y1-y2
((-2,1) and (0,-5)) line 1
line 2(0,-1) and (1,0)
first we will work for line 1
X1 is -2
X2 is -0
Y1 is 1
Y2 is -1
so y=x-1
so we substitute the values
1--1=-2--0
so,
1+1=-2+0
2=-2
-0
So the equation 1 line 1 is not true
we will now go to equation 2 line 2
the equation is 3x+y=-5
we substitute the values
3(-2--0)+1--1=-5
3(-2)+-2=-5
-6+-2=-5
-8= -5
group like terms
Ur answer should look like this -3
So the answer is 3x+y=-5
Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
Answer: 12/5 or 2 2/5
Step-by-step explanation: 7/2 - 11
/10
