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4 years ago

Carl's dog weighs 2 1/3 times what judy's dog weighs. if judy's dog weighs 35 1/2 pounds, how much does cal's dog weigh?

Mathematics

1 answer:

dangina [55]4 years ago

5 0

Cal's dog weighs approximately 94 pounds.

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Which of the following angles is coterminal with -4pi/3? -2pi/3 -pi/3 pi/3 2pi/3

PolarNik [594]

Coterminal angles are angles that end in the same position on a unit circle.

We can find angles that are coterminal to -4pi/3 by adding and subtracting 2pi.

-4pi/3 + 2pi = 2pi/3

The answer is 2pi/3

4 0

3 years ago

Do you know the inequality? Please explain and show answer :)

DerKrebs [107]

If u have a open circle, then the inequality has no equal sign. But if it is a closed circle, the inequality has an equal sign.
Shading to the left means " less then " .
Shading to the right means " greater then " .

(1) u have an open circle on -7 with shading to the left....
x < -7

(2) u have a closed circle on 4.5 with shading to the left....
x < = 4.5 (thats less then or equal)

(3) u have an open circle on -5 with shading to the right...
x > -5

(4) u have an open circle on 1.5 with shading to the right...
x > 1.5

4 0

3 years ago

Someone please help me

Anika [276]

Answer:

Step-by-step explanation:

Given

a = $\frac{1}{x}$ - $\frac{1}{y}$ = $\frac{y-x}{xy}$ ← as a single fraction

Thus

$\frac{1}{a}$ = $\frac{1}{\frac{y-x}{xy} }$ = $\frac{xy}{y-x}$ → A

6 0

3 years ago

A painter is placing a ladder to reach the third story window, which is 12 feet above the ground and makes an angle of 80 degree

mash [69]

We know that
tan ∅=opposite side angle ∅/adjacent side angle ∅
adjacent side angle ∅=opposite side angle/tan ∅

in this problem
see the attached figure to better understand the problem
angle ∅=80°
opposite side angle ∅=12 ft (AB)
adjacent side angle ∅=? (AC)
adjacent side angle ∅=12/tan 80°------> 2.12 ft

the answer is
2.12 ft

3 0

4 years ago

Use Gauss's approach to find the following sums (do not use formulas). 1+3+5+7+...999

muminat

$S=1+3+5+\cdots+995+997+999$
$S=999+997+995+\cdots+5+3+1$
$\implies 2S=(1+999)+(3+997)+(5+995)+\cdots+(995+5)+(997+3)+(999+1)$

$2S=\underbrace{1000+1000+\cdots+1000+1000}_{500\text{ times}}$

(We are adding 500 instances of 1000 because that's how many odd numbers there are between 1 and 1000, inclusive.)

$2S=500\times1000=500000$
$\implies S=250000$

4 0

4 years ago