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2 years ago

Which are zeros of the following polynomial?

Mathematics

1 answer:

g100num [7]2 years ago

8 0

Answer:

x = -2/3; x = 5/2.

Step-by-step explanation:

6x 2 - 11x - 10 = 0

Use the 'ac' method:

6 * -10 = -60. We need 2 numbers whose product is -60 and whose sum is -11.

That would be -15 and +4. So we write:

6x^2 - 15x + 4x - 10 = 0 Factor by grouping:

3x(2x - 5) + 2(2x - 5) = 0

(3x + 2)(2x - 5) = 0

x = -2/3; x = 5/2.

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Answer:

She buys 5 boxes of popcorn and 6 boxes of candy

Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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Offering 20 points for this one need asap

kirill115 [55]

Answer:

y = 3x+.5

Step-by-step explanation:

We know the y intercept (the value when x=0) is .5

We can find the slope from 2 points

(0,.5) and (1,3.5)

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3 years ago

Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

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2 years ago