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Korolek [52]
2 years ago
6

Which are zeros of the following polynomial?

Mathematics
1 answer:
g100num [7]2 years ago
8 0

Answer:

x = -2/3; x = 5/2.

Step-by-step explanation:

6x 2 - 11x - 10 = 0

Use the 'ac' method:

6 * -10 = -60. We need 2 numbers whose product is -60 and whose sum is -11.

That would be -15 and +4.  So we write:

6x^2 - 15x + 4x - 10 = 0      Factor by grouping:

3x(2x - 5) + 2(2x - 5) = 0

(3x + 2)(2x - 5) = 0

x = -2/3; x = 5/2.

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the mean average distance that jack runs in his last 10 runs is 5.7 miles. work out the distance that he would need to make this
ziro4ka [17]

Answer:

9 miles

Step-by-step explanation:

mean is calculated as

mean = \frac{sum}{count} , then

\frac{sum}{10} = 5.7 ( multiply both sides by 10 )

sum = 57

let x be the distance he needs to cover so mean is 6 , that is

\frac{sum+x}{11} = 6 ( multiply both sides by 11 )

sum + x = 66 , that is

57 + x = 66 ( subtract 57 from both sides )

x = 9

That is he would have to run 9 miles

3 0
2 years ago
The product of two numbers is 41. One of the numbers
shepuryov [24]
<h3>Answer:   5 - 4i     (choice A)</h3>

===================================================

Work Shown:

x = the other number

(5+4i)*x = 41

x = 41/(5+4i)

x = 41*(5-4i)/( (5+4i)*(5-4i) ) ..... see note below

x = 41*(5-4i)/( 41 )

x = (41/41)*(5-4i)

x = 5 - 4i  

As a way to check, (5+4i)*(5-4i) = 5^2+4^2 = 25+16 = 41

The rule used is (a-bi)(a+bi) = a^2 + b^2

-----------

Note:  I multiplied top and bottom by (5-4i) to get rid of the imaginary term in the denominator.

3 0
2 years ago
Drisen has 6 groups of trains. Each group has 3 trains in it. What addition number sentence would help him solve how many trains
Nimfa-mama [501]

Answer:

6x3=x

x=18

Step-by-step explanation: plzz mark brainliest

4 0
3 years ago
Help with this please i have a few minutes left!!!!
lara [203]
Answer: 5.44449

step-by-step explanation:
5 0
3 years ago
2x^2 / x^2 - y^2 - x^2 / xy - y ^ 2​
Juliette [100K]

Answer:

2 - 2y^2 - x/y

Step-by-step explanation:

2x^2/x^2 = 2

and

x^2/xy = x/y

therefore

2x^2/x^2 - y^2 - x^2/xy - y^2

= 2 - y^2 - x/y - y^2

= 2 - y^2 - y^2 - x/y

= 2 - 2y^2 - x/y

6 0
3 years ago
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