Question

1.) Assuming the clay blob and the superball have the same mass, and that you throw them with the same velocity, which would you throw to close the door? The clay blob will stick to the door and the superball will bounce back with almost the same speed as it had before it collided with the door. which would be more effective at closing the door - the superball or the clay of the same mass?
2.) what is the final momentum of the clay ball?

3.) how do you find the impulse of a force from the force vs. time graph?

4.) In a perfectly elastic collision between a cart and a wall, the cart would recoil with exaclty the same magnitude of momentum that it had the before the collision. because your cart's spring bumper is not perfect, you can only produce a nearly elastic collision. why is the collision made with a "springy" wall?

5.) from the above question ( question 4) how will you measure the impulse?

Answer 1

Answer:

Explanation:

1 ) The superball which bounces back with the same velocity will be more effective at closing the door . It creates greater impulse on the door because it creates more change in momentum .

2 ) The final momentum of the clay ball will be zero because its velocity after collision will be zero.

3 )  The area of force - time graph gives the value of impulse.

4 ) When the collision is made on a perfect spring , it becomes perfectly elastic . In this case the velocity of recoil is same as that before the collision . So there is no loss of energy in the collision.

5 ) The change in momentum will give the value of impulse. Since we can calculate the velocity before and after the collision , we can calculate the value of impulse. If m be the mass and v be the value of velocity before the collision

impulse = change in momentum

= m v - ( - mv )

= 2m v.