Alot as far as i know unless you need it in formal terms.
Answer:
The minimum distance in which the car will stop is
x=167.38m
Explanation:
![39.7\frac{mi}{h}*\frac{1km}{0.621371mi}*\frac{1000m}{1km}*\frac{1h}{3600s}=17.747\frac{m}{s}](https://tex.z-dn.net/?f=39.7%5Cfrac%7Bmi%7D%7Bh%7D%2A%5Cfrac%7B1km%7D%7B0.621371mi%7D%2A%5Cfrac%7B1000m%7D%7B1km%7D%2A%5Cfrac%7B1h%7D%7B3600s%7D%3D17.747%5Cfrac%7Bm%7D%7Bs%7D)
∑F=m*a
∑F=u*m*g
The force of friction is the same value but in different direction of the force moving the car so it can stop so
![F=m*a\\a=\frac{F}{m}\\a=\frac{u*m*g}{m}\\a=u*g\\a=0.096*-9.8\frac{m}{s^{2} }](https://tex.z-dn.net/?f=F%3Dm%2Aa%5C%5Ca%3D%5Cfrac%7BF%7D%7Bm%7D%5C%5Ca%3D%5Cfrac%7Bu%2Am%2Ag%7D%7Bm%7D%5C%5Ca%3Du%2Ag%5C%5Ca%3D0.096%2A-9.8%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
![a=-0.9408 \frac{m}{s^{2}}](https://tex.z-dn.net/?f=a%3D-0.9408%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D)
![v_{f}^{2}=v_{o}^{2}+2*a*(x_{f}-x_{o})\\v_{f}=0 \\x_{o}=0\\0=v_{o}^{2}+2*a*x_{f}\\x_{f}=\frac{v_{o}^{2}}{2*a} \\x_{f}=\frac{(-17.747\frac{m}{s})^{2}}{2*(-0.9408)} \\x_{f}=167.38m](https://tex.z-dn.net/?f=v_%7Bf%7D%5E%7B2%7D%3Dv_%7Bo%7D%5E%7B2%7D%2B2%2Aa%2A%28x_%7Bf%7D-x_%7Bo%7D%29%5C%5Cv_%7Bf%7D%3D0%20%5C%5Cx_%7Bo%7D%3D0%5C%5C0%3Dv_%7Bo%7D%5E%7B2%7D%2B2%2Aa%2Ax_%7Bf%7D%5C%5Cx_%7Bf%7D%3D%5Cfrac%7Bv_%7Bo%7D%5E%7B2%7D%7D%7B2%2Aa%7D%20%5C%5Cx_%7Bf%7D%3D%5Cfrac%7B%28-17.747%5Cfrac%7Bm%7D%7Bs%7D%29%5E%7B2%7D%7D%7B2%2A%28-0.9408%29%7D%20%5C%5Cx_%7Bf%7D%3D167.38m)
Answer:
The ball will have a kinetic energy of 0.615 Joules.
Explanation:
Use the kinetic energy formula
![E_k = \frac{1}{2}mv^2 = \frac{1}{2}0.032kg\cdot 6.2^2 \frac{m^2}{s^2}= 0.615J](https://tex.z-dn.net/?f=E_k%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20%5Cfrac%7B1%7D%7B2%7D0.032kg%5Ccdot%206.2%5E2%20%5Cfrac%7Bm%5E2%7D%7Bs%5E2%7D%3D%200.615J)
The kinetic energy at the moment of leaving the hand will be 0.615 Joules. (From there on, as it ball is traveling upwards, this energy will be gradually traded off with potential energy until the ball's velocity becomes zero at the apex of the flight)
Answer:
we measure sound intensity in <em><u>D</u></em><em><u>ecibels</u></em>.
Answer:
(A)
Explanation:
We know , electric potential energy between two charge particles of charges "q" and "Q" respectively is given by kqQ/r where r is the distance between them.
Since the two charged particles are moving apart, the distance between them (r) increases and thus electrical potential energy decreases.