Answer:
a = (v² – v₀²)/ 2(s – s₀)
Explanation:
v² = v₀² + 2a (s – s₀)
We can make 'a' the subject of the above expression as follow:
v² = v₀² + 2a (s – s₀)
Subtract v₀² from both side
v² – v₀² = v₀² + 2a (s – s₀) – v₀²
v² – v₀² = v₀² – v₀² + 2a (s – s₀)
v² – v₀² = 2a (s – s₀)
Divide both side by (s – s₀)
(v² – v₀²)/ (s – s₀) = 2a
Divide both side by 2
(v² – v₀²)/ (s – s₀) ÷ 2 = a
(v² – v₀²)/ (s – s₀) × 1/2 = a
(v² – v₀²)/ 2(s – s₀) = a
a = (v² – v₀²)/ 2(s – s₀)
Answer:
1.27seconds
Explanation:
Speed = 324 m/s , Distance = 411.48m
Time = Distance/Speed
Time = 411.48/324 seconds
Time = 1.27seconds ( Ans)
Answer:
The correct answer is - 30 feet.
Explanation:
According to the parking laws one should not park within 30 feet of any flashing signal, stop sign, or traffic signal it is not allowed. Parking is also not allowed in case of the following situations -
On crosswalks
In front of driveways
double parking
On sidewalks.
at "No Parking" signs are posted.
Within intersections or 20 feet of an intersection.
Within 15 feet of a fire hydrant.
The average current density is 7.6 × 10⁵ A/m².
To calculate the current density current will be 2.4 A.
Diameter of a wire = 2mm.
The cross-sectional area of the wire is given by r = d/2
where r is the radius of the wire.
Then, the cross-sectional area is = 0.00000314159265
= 3.1 × 10⁻⁶ m².
<h3>
What is average current density?</h3>
Consider a current carrying conductor, the current density depends upon the current flow in the conductor. If the current flow in the conductor will be high then the current density will also be high. Using the average current flowing through the conductor, the average current density will be found.
Average current density j = I / A Ampere/ meter².
By substituting the values in the formula,
j = 2.4 / ( 3.1 × 10⁻⁶)
= 7.6 × 10⁵ A/m².
Hence, the current density can be calculated.
Learn more about average current density,
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