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NeTakaya
3 years ago
14

Stored energy due to the interactions between objects

Physics
1 answer:
Flauer [41]3 years ago
7 0
Potential energy because it has enough energy to do work but non has been done yet.
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A 15.4 kg block is dragged over a rough, horizontal surface by a constant force of 182 N acting at an angle of 24◦ above the hor
Dima020 [189]

Answer:

Explanation:

Considering Work done by friction is asked

Given

mass of block m=15.4\ kg

force F=182\ N

inclination \theta =24^{\circ}

block is displaced by s=57.6\ m

coefficient of kinetic friction \mu _k=0.135

Friction force F_r=\mu _kN

Normal reaction N=mg-F\sin \theta =15.4\times 9.8-182\sin (24)

N=76.9\ N

Friction Force F_r=0.135\times 76.9=10.38\ N

Work done by friction force

W=f_r\cdot s

W=10.38\times 57.6=597.92\ N                        

3 0
3 years ago
i know this is a lot to do but i will give you the highest amount of points (100, but you get 50 from it.) and i will cash app y
victus00 [196]

Answer:

mel mel 4 ever

Explanation:

5 0
4 years ago
Which components of static electricity does a photocopier use?
Salsk061 [2.6K]

Answer:

For a photocopier to work, a field of positive charges must be generated on the surface of both the drum and the copy paper. These tasks are accomplished by the corona wires. These wires are subjected to a high voltage, which they subsequently transfer to the drum and paper in the form of static electricity.

8 0
2 years ago
a car advertisement states that a certain car can accelerate from rest to 70km/h in 7 seconds. find the cars acceleration
ELEN [110]
<span>a = (v2 - v1)/t= acceleration formula

a = (70 - 0)/7
a = 10 km/hr/sec
-----
It's better to use as few units as possible.
10 km/hr = 10 km*1000 m/km/(1 hr*3600 sec/hr) = 25/9 m/sec
a= 25/9 m/sec/se</span>
4 0
3 years ago
Coherent light of wavelength 540 nm passes through a pair of thin slits that are 3.4 × 10-5 m apart. At what angle away from the
Scrat [10]

Answer: 1.8\°

Explanation:

The diffraction angles \theta_{n} when we have a slit divided into n parts are obtained by the following equation:

dsin\theta_{n}=n\lambda (1)

Where:

d=3.4(10)^{-5}m is the width of the slit

\lambda=540 nm=540(10)^{-9}m is the wavelength of the light  

n is an integer different from zero.

Now, the second-order diffraction angle is given when n=2, hence equation (1) becomes:

dsin\theta_{2}=2\lambda (2)

Now we have to find the value of \theta_{2}:

sin\theta_{2}=\frac{2\lambda}{d} (3)

Then:

\theta_{2}=arcsin(\frac{2\lambda}{d})   (4)

\theta_{2}=arcsin(\frac{2(540(10)^{-9}m)}{3.4(10)^{-5}m})   (5)

Finally:

\theta_{2}=1.8\°   (6)

5 0
3 years ago
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