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kvv77 [185]
3 years ago
10

HELP PLEASEEE Angle M' is the result of its pre-image, angle sliding horizontally in a direction and vertically in a direction.

Mathematics
1 answer:
Kobotan [32]3 years ago
4 0

Answer:

angle M

horizontally in a positive

vertically in a positive

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Find the area of the shaded circle.give your answer in 3 significant numbers​
DENIUS [597]

Answer:

116 cm²

Step-by-step explanation:

The area of a circle = πr² ← r is the radius

shaded area = external area - internal area

                      = π × 6.5² - π × 2.3²

                      = π( 42.25 - 5.29)

                      = π × 36.96 ≈ 116 cm²

4 0
2 years ago
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A map of a rectangle park has a length of 4 inches
Oksanka [162]

Answer:

a map of a rectangular park has a length of 4 inches and a width of 6 inches. It uses a scale of 1 inch for every 30 miles

8 0
2 years ago
A box of cereal is reduced by 30%. The new box contains 35 ounces. How many ounces did the old box contain?
kumpel [21]

Answer:

45.5

Step-by-step explanation:

6 0
2 years ago
A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective
Inessa05 [86]

Answer:

(a) P(X \leq 20) = 0.9319

(b) Expected number of defective light bulbs = 15

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....

where, n = number of samples taken = 150

            r = number of success

           p = probability of success which in our question is % of bulbs that

                  are defective, i.e. 10%

<em>Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.</em>

So, Let X = No. of defective bulbs in a box

<u>Mean of X</u>, \mu = n \times p = 150 \times 0.10 = 15

<u>Standard deviation of X</u>, \sigma = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.7

So, X ~ N(\mu = 15, \sigma^{2} = 3.7^{2})

Now, the z score probability distribution is given by;

                Z = \frac{X-\mu}{\sigma} ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X \leq 20) = P(X < 20.5)  ---- using continuity correction

    P(X < 20.5) = P( \frac{X-\mu}{\sigma} < \frac{20.5-15}{3.7} ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = n \times p = 150 \times 0.10 = 15.

                                           

5 0
3 years ago
Si una empresa obtiene un préstamo de S/3000 a seis años de plazo, con una tasa de interés compuesto del 15 % anual capitalizabl
Debora [2.8K]

Answer:

VF= $3.281,42

Interes= 3.281,42 - 3.000= $281.42

Step-by-step explanation:

Dada la siguiente información:

Prestamo (P)= $3.000

Tasa (i)= 0,015/2= 0,0075

Cantidad de periodos (n)= 6*2= 12 semestres

<u>Para calcular el valor final del prestamos, tenemos que usar la siguiente formula:</u>

VF= P*(1 + i)^n

VF= 3.000*1,0075^12

VF= $3.281,42

Interes= 3.281,42 - 3.000= $281.42

8 0
3 years ago
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