Answer:
im pretty sure its the -3 one
Step-by-step explanation:
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
(x - 8)² + (y - 10)² = 36
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Pre-Calculus</u>
Circle Center Formula: (x - h)² + (y - k)² = r²
- <em>(h, k) </em>is center
- <em>r</em> is radius
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em>(h, k)</em> = (8, 10)
<em>r</em> = 6
<u>Step 2: Find Equation</u>
- Substitute in variables [Center Circle Formula]: (x - 8)² + (y - 10)² = 6²
- Evaluate exponents: (x - 8)² + (y - 10)² = 36
Answer:
28
Step-by-step explanation:
21^2+28^2=35^2
I believe the answer would be 6.5%
