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DerKrebs [107]
3 years ago
7

Two tiny conducting spheres are identical and carry charges of -18.4 µC and +53.0 µC. They are separated by a distance of 2.73 c

m. (a) What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive?
Physics
1 answer:
melomori [17]3 years ago
4 0

Answer:

-11776.36 N

This force is attractive since both charges are of opposite sign

Explanation:

Given that

q_1=-18.4\mu C=-18.4\times 10^{-6}C\ and\\\ q_2=53\mu C=53\times 10^{-6}C

Distance between the spheres = 2.73 cm =0.0273 m

where K is Coulomb's constant = 9.10^ 9 [N.m^2 /C^2]

According to coulombs law we know that force between two charges is given by

F = \frac{kq_1q_2}{r^2}

F = \frac{(9\times10^9)\times (-18.4 \times 10^-^6)(53  \times 10^-^6}{0.0273^2)} \\= -11776.36N

This force is attractive since both charges are of opposite sign

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y = 43.55 + 2.15t

Explanation:

We were told that in 1983, the per capita consumption was 37.1 pounds, and in 1989 it was 50 pounds.

If we assume t = 0 corresponds to year 1980. Then, for 1983 it will be t = 3 and for 1989,it will be t = 9.

Thus, expressing the information as ordered pairs, we have; (3,37. 1) and (9,50).

Let us now find slope of the linear function:

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