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3 years ago

How many millimeter are there in 10 centimeters?

Physics

2 answers:

Iteru [2.4K]3 years ago

7 0

Answer:

There are 100 millimeters in 10 centimeters.

Explanation:

Misha Larkins [42]3 years ago

5 0

Answer:

100 millimeters.....

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What discovery led J.J. Thomson to decide that atoms were not indivisible, but are actually composed of smaller parts? Thomson u

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Answer:

Thomson used a beam of negatively charged particles. Explanation: It was on a test i got it right.

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3 years ago

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During their physics field trip to the amusement park, Tyler and Maria took a rider on the Whirligig. The Whirligig ride consist

blondinia [14]

Answer:

Speed = 7.04434 m/s

Explanation:

Given that:

The radius of the circle = 6.5 m

The expression for the calculation of circumference is shown below as:

$Circumference=2\times \pi \times radius$

Thus,

$Circumference=2\times \frac{22}{7} \times 6.5\ m=40.8572\ m$

Time taken = 5.8 seconds.

Thus, The speed is:

$Speed=\frac{Circumference}{Time\ Taken}$

So,

$Speed=\frac{40.8572}{5.8}\ m/s$

Speed = 7.04434 m/s

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4 years ago

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A capacitor stores 7.77 x 10-7 J of

Lubov Fominskaja [6]

Answer: $36.22\ V$

Explanation:

Given

Energy in a capacitor $E=7.77\times 10^{-7}\ J$

Charge $Q=4.29\times 10^{-8}\ C$

Energy of a capacitor is given by

$E=\dfrac{1}{2}CV^2=\dfrac{1}{2}QV\quad [\text{Q=CV}]$

Insert the values

$E=\dfrac{1}{2}QV\\\\\Rightarrow 7.77\times 10^{-7}=\dfrac{1}{2}\times 4.29\times 10^{-8}\times V\\\\\Rightarrow V=3.622\times 10\\\\\Rightarrow V=36.22\ V$

Thus, the voltage around the capacitor is $36.22\ V$

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3 years ago

If the mass of the body is tripled and its velocity becomes doubled, then the linear momentum of the body will

Klio2033 [76]

Answer:

don't know I is not am studnt

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3 years ago

Find the net work done by friction on the body of a snake slithering in a complete circle of radius. The coefficient of friction

Tamiku [17]

Answer:

C. 0 J

Explanation:

When an object moves in a circle, friction provides the centripetal force. Hence, it is acting towards the centre of the circle. The displacement of the object is tangential to the circle at the point of interest. Hence, the angle between the frictional force and the displacement is 90°.

Work done is given by

W = Fd cos θ

where F is the force, d is the displacement and θ is the angle between them.

W = Fd cos 90° = 0 J

Hence, the work done by friction is 0 J.

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3 years ago