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aksik [14]
3 years ago
14

A greyhound's velocity changes from rest to 19 m/s in 2 seconds. What is the greyhound's average acceleration?

Physics
2 answers:
Arturiano [62]3 years ago
7 0
We know, a = (v₂-v₁) / (t₂-t₁)
Here, v₂-v₁ = 19 m/s
t₂-t₁ = 2 s

Substitute it into expression, 
a = 19/2
a = 9.5 m/s²

So, your final answer is 9.5 m/s²

Hope this helps!
vfiekz [6]3 years ago
6 0
The correct answer is 9.5 m/s^2. I just took this test.
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How does the lever arm change if you decrease the angle of the force?
Vladimir79 [104]

Answer:

The lever arm could decrease or increase depending of the initial angle.

Explanation:

The lever arm d is calculated by:

d = rsin(θ)

where r is the radius and θ the angle between the force and the radius.

So, the increse or decrees of d depends of the sin of the angle θ, if the initial angle is greather than 90° and the angle decrease to an angle closer to 90°, the lever arm will increase but if the initial angle is 90° or lower and the angle decrease, the lever arm will decrease.

8 0
3 years ago
During a plane showcase, a pilot makes circular "looping" with a speed equal to the sound speed (340 m/s). However, the pilot ca
Dmitriy789 [7]

Answer:

1472.98 m

Explanation:

Data provided:

Speed of circular looping, v = 340 m/s

Acceleration, a = 8g

here,

g is the acceleration due to the gravity = 9.81 m/s²

Now,

the centripetal acceleration is given as,

a=\frac{v^2}{r}

r is the radius of the loop

on substituting the respective values, we get

8\times9.81=\frac{340^2}{r}

or

r = 1472.98 m

5 0
3 years ago
If a system has 225 kcal of work done to it, and releases 5.00 × 102 kj of heat into its surroundings, what is the change in int
vovikov84 [41]

We can solve the problem by using the first law of thermodynamics:

\Delta U = Q-W

where

\Delta U is the change in internal energy of the system

Q is the heat absorbed by the system

W is the work done by the system on the surrounding


In this problem, the work done by the system is

W=-225 kcal=-941.4 kJ

with a negative sign because the work is done by the surrounding on the system, while the heat absorbed is

Q=-5 \cdot 10^2 kJ=-500 kJ

with a negative sign as well because it is released by the system.


Therefore, by using the initial equation, we find

\Delta U=Q-W=-500 kJ+941.4 kJ=441.4 kJ

8 0
3 years ago
How does air pressure change with altitude?
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3 0
3 years ago
What would you predict for this elephant's stride frequency? That is, how many steps per minute will the elephant take?
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8 0
3 years ago
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