Answer:
10010
Step-by-step explanation:


So
gives us:



-----------------------------------------------------
Combine like terms:


We aren't allowed to have a coefficient bigger than 1.
I'm going to replace
with 1 and
with
:

I want a
number:

Combine like terms:

:

Combine like terms:

We can rewrite the first term by law of exponents:


So the binary form is:

Maybe you like this way more:
Keep in mind 1+1=10 and that 1+1+1=11:
Setup:
1 0 1 1
+ 1 1 1
------------------------------
(1) (1) (1)
1 0 1 1
+ 1 1 1
------------------------------
1 0 0 1 0
I had to do some carry over with my 1+1=10 and 1+1+1=11.
Answer:d=5/3x
Step-by-step explanation:
Let's solve for d.
(2/3x)(d)=10/9
Step 1: Divide both sides by (2x)/3.
2/3dx / 2x/3=10/9 / 2x/3
d=5/3x
Answer:
m∠P ≅ m∠L; this can be confirmed by translating point P to point L.
Step-by-step explanation:
Angle angle (AA) similarity postulate state that two triangles are similar if two of their corresponding angle is similar. The corresponding angle for each point of the triangles will be:
∠L=∠P
∠Q=∠M
∠N=∠R
Since the 2nd triangle made from dilation, it should maintain its orientation.
Option 1 is true, ∠P corresponds to ∠L. If you move/translate point P to point L, you can confirm it because their orientation is the same.
Option 2 is false, the triangle will be similar if ∠P=∠N but you can't confirm it with translation alone.
Option 3 and 4 definitely wrong because it speaking about length, not the angle.
<span>A wok frying pan is shaped like a spherical bowl with handles. A bit of experimentation at home persuades a cook that a wok holds about 3 L</span>
I think the answer is 180 since 360/2=180