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irakobra [83]
3 years ago
6

Let S = {1,2,3,4,5,6,7,8,9,10} be the set of equally likely outcomes for an event. Let event E = {1,2,3,4,5,6} and event F = {2,

4,6,8}.
Drag each probability to its proper column. (Note: Ec means "the complement of E")
P(E and Fc)P(E or F)P(E)P(Ec or Fc)P(Ec)P(F)P(Fc)
0.3
0.4
0.6
0.7

Mathematics
1 answer:
Ganezh [65]3 years ago
4 0

Answers:

0.3= P( E AND F ^c)

0.4 = P(F) and P(E^c)

0.6= P(E) and P( F^c)

0.7 = P( E or F) and P(E ^c or F ^c)

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