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MAXImum [283]
3 years ago
9

I need help with this question.

Mathematics
2 answers:
kykrilka [37]3 years ago
4 0

She can choose any one of 3 sweaters. <u>For each</u> choice of sweater . . .

She can choose any one of 4 skirts.

The total number of different ways to choose an outfit = (3 x 4) = 12 .
laiz [17]3 years ago
3 0
12 possible outcomes.

Sweater A
Sweater B
Sweater C

Skirt 1
Skirt 2
Skirt 3
Skirt 4

Possible ways:

A1, A2, A3, A4
B1, B2, B3, B4
C1, C2, C3, C4

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The weight in pounds of a baby in the first six months of life can be modeled by the
gavmur [86]

Answer:

14.5

Step-by-step explanation:

You would plug 5 into the equation for m and have w = 1.5 (5) + 7

Then you would multiply 1.5 and 5 and get 7.5 and then add 7 and get 14.5

6 0
3 years ago
Ahmed found the volume of a cone having both a height and a diameter of 6 centimeters. His work is shown below. Step 1 Find the
kaheart [24]

Answer:

C- step 3, the resulting area should be in terms of pi

Step-by-step explanation:

I did the test on edge, I passed

8 0
2 years ago
Read 2 more answers
Please help and show work ​
san4es73 [151]

Step-by-step explanation:

Since PT = 2PM and AR = 2AD,

The midsegment MD must be the average of PA and TR:

Therefore we have

2(20x + 4) = 10 + (34x + 16)

=> 40x + 8 = 34x + 26

=> 6x = 18

=> x = 3

Hence length of MD

= 40(3) + 8 = 128.

8 0
3 years ago
Solve the equation:<br> [3 2<br> 5 5]<br><br> [x1<br> x2]+<br> [1<br> 2]=<br> [2<br> -3]
dsp73

9514 1404 393

Answer:

  (x1, x2) = (3, -4)

Step-by-step explanation:

As with any 2-step linear equation, subtract the constant, then multiply by the inverse of the coefficient of the variable.

  \left[\begin{array}{cc}3&2\\5&5\end{array}\right]\left[\begin{array}{c}x\\y\end{array}\right]+\left[\begin{array}{c}1\\2\end{array}\right]=\left[\begin{array}{c}2\\-3\end{array}\right]\\\\\left[\begin{array}{cc}3&2\\5&5\end{array}\right]\left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}1\\-5\end{array}\right]\\\\\left[\begin{array}{c}x\\y\end{array}\right]=\dfrac{1}{5}\left[\begin{array}{cc}5&-2\\-5&3\end{array}\right]\left[\begin{array}{c}1\\-5\end{array}\right]

Performing the multiplication of the matrix by the vector gives the solution.

  x = ((5)(1) +(-2)(-5))/5 = 15/5 = 3

  y = ((-5)(1) +(3)(-5))/5 = -20/5 = -4

Using your variables, x1, x2, the solution is ...

  (x1, x2) = (3, -4)

7 0
2 years ago
Please I need to know if its true or false please lmk!!!​
Papessa [141]

Answer:

False

Step-by-step explanation:

<u>According to the complex conjugate root theorem:</u>

if a complex number is a root of a polynomial, its conjugate is also the root of the polynomial

We are given all the roots of the polynomial and there is only one complex root

Since according to the complex conjugate root theorem, there can be either none or at least 2 complex roots of a polynomial

We can say that this set of roots of a polynomial is incorrect

7 0
2 years ago
Read 2 more answers
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