Formula for momentum is mass times velocity so you do 52 kg times 5 m/s and that equals 260 kg x m/s
Given that,
mass m = 110 lbs
Force of gravity in Newton, F =?
Since,
1 lbs = 0.45 kg
110 lbs = 110* 0.45 = 49.5 kg
Since, force of gravity equals the weight of the body.
F = W = mg = 49.5 * 9.81
F = 485.595 N
Force of gravity will be 485.595 N.
In order for motion to occur net force is greater than 485.595 N.
The same power (1.9×10^4 watts) gets diminished by Inverse square law
<span>(ratio of distances)² </span>
<span>= (138/70000)² </span>
<span>= 3.886506 X 10^-6 . </span>
<span>This is the diminution factor for the given sensitivity of the telescope. But at 3.8865 millionth below the sensitivity its is far below detection; it needs to be enhanced by collecting the energy over an area so many times more (by an aperture multiplied by same factor) </span>
<span>1/[3.886506 X 10^-6] = 257298.88 </span>
<span>In other words the diameter should have the ratio of square root of this </span>
<span>(70000/138). </span>
<span>This multiplied by 300m dish gives </span>
<span>300 X (70000/138) = 152173.913 m = 152.1739 km. </span>
<span>This should be the aperture of the new telescope for detecting the signal.</span>
Answer:
Vi = 4.38 m/s
Explanation:
Given
m = 1000 kg ;
y = 8m ;
T = 11000 N;
∑Fy = m*a
W - T = m * a
(1000kg * 9.8 m/s² ) - 11000N = 1000 kg * a
a = - 1.2 m/s²
Using the equation from parabolic motion
Vf ² = Vi² + 2*a*y
Solve to Vi
Vi = √ 2* 1.2m/s² * 8 m
Vi = √19.2 m²/s²
Vi = 4.38 m/s
Its option no 2
as enormous amount of energy is released in fusion reaction at sun