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shutvik [7]
3 years ago
11

How many hours will it take to fill a cubic vat of 15.7 ft edge length with a liquid that has a density of 1.31 g/mL and is spil

ling at a rate of 2.30 kg/s
Physics
1 answer:
Delicious77 [7]3 years ago
8 0

Answer:

240 s or 4 minutes.

Explanation:

Given that

Volume of the cubic vat is 15.7³ = 3869.893 ft³

Density of the liquid is 1.31 g/mL

For easier calculations, we need to convert the density from g/mL to ft³

conversion factors shall be CUBED in order to do it!

We know that

1 inch = 2.54 cm, and

1 foot = 12 in

This means that

1.31 g/cm³ * 2.54³ cm³/in³ * 12³ in³/ft³

= 37095.069 g/ft³

Lastly,

We use this conversion method

1 second/ 2300 grams * 37095.069 g/ft = 16.13 ft³/s

Bringing down the volume of the cube, we use it to divide, and thus

3869.893 / 16.13 = 240 seconds

240 seconds = 4 minutes

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The index of refraction for red light in water is 1.331 and that for blue light is 1.340. A ray of white light enters the water
Alex Ar [27]

Answer:

(a) 47.08°

(b) 47.50°

Explanation:

Angle of incidence  = 78.9°

<u>For blue light : </u>

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for blue light which is 1.340

n₁ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.340}

{sin\theta_2}=0.7323

Angle of refraction for blue light = sin⁻¹ 0.7323 = 47.08°.

<u>For red light : </u>

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for red light which is 1.331

n₁ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.331}

{sin\theta_2}=0.7373

Angle of refraction for red light = sin⁻¹ 0.7373 = 47.50°.

5 0
4 years ago
Which of the following statements are true about magnets?
timama [110]
The correct answer is 3
4 0
3 years ago
Two resistors with values of 6.0 W and 12 W are connected in parallel. This combination is connected in series with a 2.0 W resi
Murljashka [212]
Well, first of all, you really shouldn't use ' W ' for the unit when you
talk about resistors.

You may have seen the resistors written as 6ω, 12ω, and 2ω in your
book or on the homework sheet. But that little symbol ' ω ' is not a ' w '.
It's the small Greek letter 'omega'. The CAPITAL omega is ' Ω '. It's used
to label resistors because it's short for "ohms". So the resistors in this
problem have resistances of 6Ω, 12Ω, and 2Ω, and we have to do some
manipulating of the individual resistors to find out what resistance the
battery actually sees.

The parallel combination of the first two resistors looks like a single
resistor, whose value is

1 / (1/6 + 1/12)

= 1 / (2/12 + 1/12)

= 1 / (3/12)

= 12/3 = 4Ω .

Now, that parallel combination is connected in series with 2Ω .
All three resistors together look like a single resistor of

4Ω + 2Ω = 6Ω .

So the battery thinks there's a single resistor connected to it,
with 6Ω of resistance. The current out of the battery is

I = V / R = (24v) / (6Ω) = 4 Amperes.

That 4 Amperes of current will split between the parallel resistors,
but it will ALL flow through the series 2Ω resistor because there's
no other path through that part of the circuit.

So the current through the 2Ω resistor is 4 Amperes. (B).

Note:
The POWER dissipated by the 2Ω resistor is

P = I² R = (4A)² · (2Ω) = 32 watts .

This is a fair amount of heat, so you'll need to provide some way
to remove the heat from the resistor, otherwise it'll burn or crack.
8 0
3 years ago
After World War II the U.S. Air Force carried out experiments on the amount of acceleration a human can survive. These experimen
adell [148]

Answer:

11.9051g

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.8 m/s²

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\frac{70-140}{0.6}\\\Rightarrow a=-116.67\ m/s^2

Absolute value of the (negative) average acceleration is 116.67 m/s²

\dfrac{a}{g}=\dfrac{116.67}{9.8}\\\Rightarrow a=11.9051g

The deceleration was 11.9051g

8 0
4 years ago
Which letter represents the location of the<br> resister in this diagram?<br> A<br> B<br> C<br> D
ololo11 [35]

Answer:

The letter B is the letter that represents the location of the resister in the diagram.

Explanation:

I hope it helped!Please mark brainliest and have a wonderful night! and day!!!!

5 0
4 years ago
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