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3 years ago

What a medium-mass star becomes at the end of its life?

Physics

1 answer:

Reika [66]3 years ago

7 0

Answer:

What a medium-mass star becomes after a planetary nebula; a very bright, dense mass about the size of the planet Earth. ... The process that generates all of the energy that a star produces. Supernova. A Red Super Giant explodes into this when it runs out of elements to fuse together.

Explanation:

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A car is travelling at 20 km/hr.It speeds upto 60 km/hr in 6 seconds.What is its acceleration?

Anastaziya [24]

A=v/t

40/6=a=20/3
...........

4 0

3 years ago

The climate of an area is based on A) Rivers and lakes B) natural resources. C) mountain and valleys. D) Precipitation and tempe

LenaWriter [7]

It is D as it is the only answer referring to weather and climate.

3 0

3 years ago

According to the impulse--momentum equation Ft = change in mv, a bungee jumper in fall has momentum which is reduced by the forc

Dima020 [189]

Answer:

The answer is a. Jumper

Explanation:

The change in the momentum is represented by the equation

$Ft=m*v$

Acceleration of any body is calculated by the product of the mass of the body and with the velocity the same mass is moving.

Since it is mentioned in the statement that m is the mass of the jumper then velocity will also be of the jumper to calculate the change in the momentum.

If the mass of bugle cord is taken, then its velocity will be taken for the equation.

6 0

3 years ago

A simple pendulum of length of 1.37 m and mass of 6.66 kg is given an initial speed of 2.85 m/s at its equilibrium position. Det

yawa3891 [41]

Answer:

2.35 s

Explanation:

The period of a simple pendulum is expressed as;

T = 2π $\sqrt{\frac{L}{g} }$

Where

T is the period in seconds

L is the length in metres

g is acceleration due to gravity

T = 2π $\sqrt{\frac{1.37}{9.8}}$

T = 2.349 s

T = 2.35 s

8 0

4 years ago

A proposed space station includes living quarters in a circular ring 45.0 m in diameter.

siniylev [52]

Answer:

Angular speed, $\omega=0.65\ rad/s$

Explanation:

Given that,

Diameter of the circular ring, D = 45 m

Radius, r = 22.5 m

Let $\omega$ is the angular speed should the ring rotate so the occupants feel that they have the same weight as they do on Earth. It can be given by providing the centripetal force to the normal force as :

$mg=m\omega^2r$

$\omega=\sqrt{\dfrac{g}{r}}$

$\omega=\sqrt{\dfrac{9.8\ m/s^2}{22.5\ m}}$

$\omega=0.65\ rad/s$

So, the angular speed of the ring is 0.65 rad/s. Hence, this is the required solution.

6 0

3 years ago