propagated disturbance is a variation
Hello
1) First of all, since we know the radius of the wire (

), we can calculate its cross-sectional area

2) Then, we can calculate the current density J inside the wire. Since we know the current,

, and the area calculated at the previous step, we have

3) Finally, we can calculate the electric field E applied to the wire. Given the conductivity

of the aluminium, the electric field is given by
Answer:
, 
Explanation:
The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:

where
k is the Coulomb constant
e is the magnitude of the charge of the electron
e is the magnitude of the charge of the proton in the nucleus
r is the distance between the electron and the nucleus
v is the speed of the electron
is the mass of the electron
Solving for v, we find

Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately

while the electron mass is

and the charge is

Substituting into the formula, we find

Answer:
K_{total} = 19.4 J
Explanation:
The total kinetic energy that is formed by the linear part and the rotational part is requested

let's look for each energy
linear
= ½ m v²
rotation
= ½ I w²
the moment of inertia of a solid sphere is
I = 2/5 m r²
we substitute
= ½ mv² + ½ I w²
angular and linear velocity are related
v = w r
we substitute
K_{total} = ½ m w² r² + ½ (2/5 m r²) w²
K_{total} = m w² r² (½ + 1/5)
K_{total} =
m w² r²
let's calculate
K_{total} =
6.40 16.0² 0.130²
K_{total} = 19.4 J