Answer:
The instantaneous velocity of the object is 250 m/s
Explanation:
Given;
time of the object motion, t = 25 s
acceleration due to gravity, g = 10 m/s²
The instantaneous velocity of the object is given as;
v = u + gt
where;
u is the initial velocity of the object = 0 (since it was released from rest)
Substitute the givens;
v = 0 + (10 x 25)
v = 250 m/s
Therefore, the instantaneous velocity of the object is 250 m/s
Answer:
2.2 m/s
Explanation:
<u>solution:</u>
To calculate change in stored energy at desired extension
ΔU = 1/2*k*(δx)^2
= 1/2*3700*(0.37^2-0.180^2)
= 201 N.m
use work energy theorem
ΔU = ΔK = 1/2*m*v^2 = 201
= 2.2 m/s
<u>note:</u>
calculation maybe wrong but method is correct.
Answer:
option 4 is the correct answer
<span>a) write a polynomial expression for the position of the particle at any time t greater or equal to zero.
</span>Position is found by integrating velocity:
<span>s(t) = (t^3)/3 - 4t^2 + 7t + c
</span>where c is a constant corresponding to the position at t=0. <span>
b) at what time(s) is the particle changing direction
</span>the particle changes direction whenever the velocity is zero; the velocity function equals
<span>(t-1)(t-7) a difference of squares so the zeros are 1 and 7, it changes direction at 1 second and 7 seconds. </span><span>
c) find the total distance traveled by the particle from t=0 and t=4
</span><span>s(0) = c
s(1) = 8/3 + c
s(4) = 64/3 - 64 + 28 + c.
</span>
from 0 to 1 the particle travels 8/3 units. From 1 to 4 it travels -(64/3 - 36 - 8/3) = (-(56/3 - 108/3))
<span>=-(-52/3) = 52/3 units
</span>
<span>so in total it travels 52/3 + 8/3 =20 units</span>
I really don’t know I just need some points to help me though this test I’m very sorry
