If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).
Answer: 0.9
Explanation:
For an inclined surface the coefficient of friction (n) is the ratio of the moving force (Fm) to the normal reaction (R) acting on the body.
n = Fm/R
Fm = WSintheta = mgsintheta
R = Wcostheta = mgcostheta
n = Wsintheta/Wcostheta
n = sintheta/costheta
n = tan theta
n = tan 42°
n = 0.9
Therefore, minimum coefficient of static friction between the vehicle’s tires and the road is 0.9
Answer:
Explanation:
Answer:
Explanation:
The half life is the time taken for half of a radioactive substance to disintegrate.
The shorter the half life, the larger the decay constant and the faster the decay process.
For a very large half life, it would take a very long time for the radioactive nuclide to decay to half.
With each half life reached, a new set of daughter cell is formed. Atoms that have short half life would decay rapidly. Every radionuclide has its own characteristic half-life.
If the number of half-lives increases, then the number of radioactive atoms decreases, because approximately half of the atoms' nuclei decay with each half-life. With this observation, we can hypothesise and conduct experiment to support the assertion that as the number of half-lives increases then the number of radioactive atoms decreases.
Hi there!
To find the final velocity of an object dropped from rest, we can used the simplified equation:
vf = √2gh
Plug in the given values: (g = 9.8 m/s²)
vf = √2(9.8)(100) ≈ 44.272 m/s