A. The horizontal velocity is
vx = dx/dt = π - 4πsin (4πt + π/2)
vx = π - 4π sin (0 + π/2)
vx = π - 4π (1)
vx = -3π
b. vy = 4π cos (4πt + π/2)
vy = 0
c. m = sin(4πt + π/2) / [<span>πt + cos(4πt + π/2)]
d. m = </span>sin(4π/6 + π/2) / [π/6 + cos(4π/6 + π/2)]
e. t = -1.0
f. t = -0.35
g. Solve for t
vx = π - 4πsin (4πt + π/2) = 0
Then substitute back to solve for vxmax
h. Solve for t
vy = 4π cos (4πt + π/2) = 0
The substitute back to solve for vymax
i. s(t) = [<span>x(t)^2 + y</span>(t)^2]^(1/2)
h. s'(t) = d [x(t)^2 + y(t)^2]^(1/2) / dt
k and l. Solve for the values of t
d [x(t)^2 + y(t)^2]^(1/2) / dt = 0
And substitute to determine the maximum and minimum speeds.
Answer:
m1 = √2kg , m2 = 1kg , m3 = 1kg
Explanation:
Since the mass m1 can't move, the sum of horizontal and vertical forces must be zero. Since the mass m1 is suspended symmetrically the horizontal forces are equal if mass m2 and m3 are equal.
The tension in each string suspending mass m1 must match the force of gravity pulling on m1. The tension in each string is:
T = m2*g = m3*g = g
The vertical forces pulling m1 up is therefore: 2 * T * cos 45° = √2 * T = √2 * g
This force must match the force of gravity G pulling m1 down. G = m1 * g
Combining both equations: √2 * g = m1 * g
m1 = √2
Answer:
L = 1.023 H
Explanation:
given,
radius of the cylindrical solenoid = r = 0.6 m
Number of turns = N = 600
Length = l = 0.5 m
Current in the cylindrical solenoid = 15 A
Inductance in the coil = ?
using formula
L = 1.023 H
the inductance L of the coil is = 1.023 H
The answer is it's middle the nueculs