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sladkih [1.3K]
3 years ago
5

9) Because of friction A) energy is NOT always conserved. B) NOT all potential energy is converted to kinetic energy. C) all of

an object's kinetic energy turns into potential energy. D) all of an object's potential energy turns into kinetic energy.
Physics
2 answers:
ehidna [41]3 years ago
8 0
<h2>Answer:</h2>

<u>The right choice is </u><u>(B) NOT all potential energy is converted to kinetic energy.</u>

<h2>Explanation:</h2>

Friction is a repulsive or resistive force to motion of any body in motion. When two bodies move against each other some of the kinetic energy is converted to heat energy due to friction. This reduces the total kinetic energy in the system.  In other words we can say that when two contacting surfaces move relative to each other, the friction between the two surfaces converts kinetic energy into thermal energy, or heat.

Nina [5.8K]3 years ago
6 0
<h2>Hello!</h2>

The answer is: B) NOT all potential energy is converted to kinetic energy

<h2>Why?</h2>

Let's discard each option in order to find the correct option:

A) energy is NOT always conserved, False: Energy is always conserved, energy can turn to another kind of energy but the energy will be always conserved.

B) NOT all potential energy is converted to kinetic energy, True: We must remember that Energy of Friction usually opposes to the movement of a body, so, it means that all the potential energy (work) applied to an object would not be converted into kinetic energy (movement).

C) all of an object's kinetic energy turns into potential energy, false: Since the Energy of Friction is acting, not all of the kinetic energy will be turned into potential energy.

D) all of an object's potential energy turns into kinetic energy, false: Since B is true, D is false, not all potential energy is converted to kinetic energy because of the energy of friction.

Have a nice day!

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A cylindrical container closed of both end has a radius of 7cm and height of 6cm A.)find the total surface area of the container
Natalka [10]

Given:

A cylindrical container closed of both end has a radius of 7cm and height of 6cm.

Explanation:

A.) Find the total surface area of the container.

  • A = 2πrh + 2πr²
  • A = 2(3.14)(7)(6) + 2(3.14)(7 × 7)
  • A = 263.76 + 307.72
  • A = 571.48

B.) Find the volume of the container.

  • V = πr²h
  • V = (3.14)(7×7)(6)
  • V = 923.16

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3 years ago
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Consider a household that uses 14,000 kWh of electricity and 900 gal of fuel oil, per year, during a heating season. The average
ryzh [129]

Answer:

9517.2 lbm

Explanation:

Electricity consumption = 14000 kWh/year

Fuel consumption = 900 gal/year

Amount of CO₂ produced per gallon = 26.4 lbm/gal

Amount of CO₂ produced per kWh = 1.54 lbm/kWh

Amount of CO₂ produced in one year

14000\times 1.54+900\times 26.4=45320\ lbm

Reduction would be

0.21\times 45320=9517.2\ lbm

The reduction in the amount of CO₂ produced is 9517.2 lbm

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4 years ago
A 3.3 kg ball sits on the ground and is kicked with a FAPP of 36N
jeyben [28]

a) 32.3 N

The force of gravity (also called weight) on an object is given by

W = mg

where

m is the mass of the object

g is the acceleration of gravity

For the ball in the problem,

m = 3.3 kg

g = 9.8 m/s^2

Substituting, we find the force of gravity on the ball:

W=(3.3)(9.8)=32.3 N

b) 48.3 N

The force applied

F_{app} = 36 N

The ball is kicked with this force, so we can assume that the kick is horizontal.

This means that the applied force and the weight are perpendicular to each other. Therefore, we can find the net force by using Pythagorean's theorem:

F=\sqrt{W^2+F_{app}^2}

And substituting

W = 32.3 N

Fapp = 36 N

We find

F=\sqrt{32.3^2+36^2}=48.3 N

c) 14.6 m/s^2

The ball's acceleration can be found by using Newton's second law, which states that

F = ma

where

F is the net force on an object

m is its mass

a is its acceleration

For the ball in this problem,

m = 3.3 kg

F = 48.3 N

Solving the equation for a, we find

a=\frac{F}{m}=\frac{48.3}{3.3}=14.6 m/s^2

8 0
4 years ago
A constant force of magnitude F acts on an object of mass 0.04kg initially at rest at a point O. If the speed of the object when
vampirchik [111]

Answer:

F = 100 Newtons

Explanation:

F = ?

m = 0.04kg

u = 0m/s ==> u is just an abbreviation for initial velocity, it is conventional.

s = 50m ==> s is just an abbreviation for distance, it is conventional.

v = 500m/s ==> v is just an abbreviation for final velocity, it is conventional.

v^{2} = u^{2} + 2as\\\\=> a = \frac{v^{2} - u^{2}}{2s}\\a = \frac{500^{2} }{2*50}\\a = 2500ms^{-2}

Then F = ma = 0.04 x 2500 = 100N

5 0
3 years ago
A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.65 ms from an initial spe
dezoksy [38]

Answer:

the magnitude of the average contact force exerted on the leg is  3466.98 N

Explanation:

Given the data in the question;

Initial velocity of hand v₀ = 5.25 m/s

final velocity of hand v = 0 m/s

time interval t = 2.65 ms = 0.00265 s

mass of hand m = 1.75 kg

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we substitute

F_{hand × 0.00265  = 1.75( 0 - 5.25 )

F_{hand × 0.00265  = 1.75( - 5.25 )

F_{hand × 0.00265  = -9.1875

F_{hand = -9.1875 / 0.00265  

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Next we determine force on the leg F_{leg

Using Newton's third law of motion

for every action, there is an equal opposite reaction;

so, F_{leg = - F_{hand

we substitute

F_{leg = - ( -3466.98 N )

F_{leg = 3466.98 N

Therefore, the magnitude of the average contact force exerted on the leg is  3466.98 N

5 0
3 years ago
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