Ask question

Ask question

All categories

3 years ago

9

There are six rows 18 chairs in each row in the center of the chairs for four rows of six chairs are brown the rest of the chair

s are blue how many chairs are blue

1 answer:

AURORKA [14]3 years ago

7 0

What you do is subtract 6-4=2

You might be interested in

{3x+y=7{-2x+y=-3 please

fredd [130]

Answer:

x= $\frac{4}{5}$

y= $\frac{23}{5}$

Step-by-step explanation:

Look at the pictures!

7 0

2 years ago

If a ball is thrown directly upward with a velocity of 50ft/s, it's height (in feet) after t seconds is given by y=50t-16t^2 wha

Tomtit [17]

Answer:

39.0625 ft

Step-by-step explanation:

Since the function is a quadratic representing height, and the coefficient of the t² is negative, the vertex of the parabola will be the maximum height achieved by the ball.

The general form for a quadratic equation is ax² + bx + c, here a is -16, and b is 50

To find the x coordinate of the vertex, use x = -b/(2a)

We have x = -50/[2(-16)]

x = -50/-32

x= 25/16

Now plug that into the equation to find the y value, which will be the height...

y = 50(25/16) - 16(25/16)²

y = 1250/16 - 16(625/256)

y = 1250/16 - 625/16

y = 625/16

y = 39.0625

7 0

2 years ago

Consider a Poisson distribution with μ = 6.

bearhunter [10]

Answer:

a) $P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b) f(2) = 0.04462

c) f(1) = 0.01487

d) $P(X \geq 2) = 0.93803$

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In this question:

$\mu = 6$

a. Write the appropriate Poisson probability function.

Considering $\mu = 6$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b. Compute f (2).

This is P(X = 2). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

So f(2) = 0.04462

c. Compute f (1).

This is P(X = 1). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

So f(1) = 0.01487.

d. Compute P(x≥2)

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

Then

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.06197 = 0.93803$

So

$P(X \geq 2) = 0.93803$

5 0

2 years ago

What day and time will it be 85 hr 33 min after Friday 12:11 am?

marishachu [46]

Answer:

Enter date and time information at "From:"

Select a month and a day. Enter a year.

The year entered must be a positive number. Not zero (0).

Enter hours and minutes. Select am or pm.

The hours entered must be a positive number between 1 and 12 or zero (0).

The minutes entered must be a positive number between 1 and 59 or zero (0).

Add or Subtract Line

Enter number of days, hours and minutes

Select "add" or "subtract"

If you type "ghblxz", in the year box the computer will print "0"

If you type "1.9e2", the computer will use "190" to calculate the answer.

If you select "February 31", the computer will print "Not a Day"

Click "Click to Calculate" button. The calculated date and time will appear.

NaN = not a number

To clear the entry boxes click "Reset

5 0

2 years ago

1 minus 2 over x minus 3 over x squared divided by 1 minus 9 over x squared

Wittaler [7]

Are you familiar with PEMDAS?

<span />

8 0

2 years ago