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Mrac [35]
4 years ago
11

PLZ AMWSER, find the area for the circle, will mark brainest, plz tell me what u did to get the ANWSER

Mathematics
2 answers:
strojnjashka [21]4 years ago
5 0

Answer:

area = 81π in² (or ≈ 254.47 in²)

Step-by-step explanation:

The formula for an area of a circle is  area = πr².

You are given the diameter, which is 18 in.

diameter = radius (2)

So to get radius, divide the diameter in half:

18/2 = 9.

Now that we have the radius, put that back into the formula for the area of a circle:

area= π9²

Then, solve for the 9², which will be 81 and put it back into the formula.

area = 81π in²

If you need to get rid of the π, the answer will be about 254.47 in²

Talja [164]4 years ago
3 0

Answer:

254.34

Step-by-step explanation:

3.14*9^2

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Morgarella [4.7K]

Answer:

7 1/2 hours I believe is the correct answer. Hope it works!

6 0
3 years ago
Read 2 more answers
MULTIPLE CHOICE QUESTION
Paha777 [63]

Answer:

i think it will be #3

Step-by-step explanation:

3 0
3 years ago
In 3-4 sentences, describe how you would find a line parallel to the line 2x + 5y = 15 that goes through the point (-10, 1). Be
larisa86 [58]

the parallel line is 2x+5y+15=0.

Step-by-step explanation:

ok I hope it will work

soo,

Solution

given,

given parallel line 2x+5y=15

which goes through the point (-10,1)

now,

let 2x+5y=15 be equation no.1

then the line which is parallel to the equation 1st

2 x+5y+k = 0 let it be equation no.2

now the equation no.2 passes through the point (-10,1)

or, 2x+5y+k =0

or, 2*-10+5*1+k= 0

or, -20+5+k= 0

or, -15+k= 0

or, k= 15

putting the value of k in equation no.2 we get,

or, 2x+5y+k=0

or, 2x+5y+15=0

which is a required line.

6 0
1 year ago
I dont know the answer!! I give brainlist...​
iragen [17]

Answer:

A.   (f + g)(1) = - 9

B.    (f - g)(0) = -7

C.    (fg)(3) = 0

Step-by-step explanation:

A.    (f + g)(1) = f(1) + g(1)               f(1) = 1^2 - 9 = 1 - 9 = - 8       g(1) = 1 - 2 = - 1

                    = -8 -1 = -9

B.     (f - g)(0) = f(0) - g(0)             f(0) = 0^2 - 9 = 0 - 9 =  -9      g(0) = 0 - 2 = -2

                      =  -9 + 2 = -7

C.      (fg)(3) = f(3)(g(3)                   f(3) = 3^2 - 9 = 9 - 9 = 0    g(3) = 3 - 2 = 1

                    = 0(1) = 0

4 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
Elena L [17]

Answer:

First option is the right choice.

Step-by-step explanation:

\frac{1}{\cos \left(x\right)+1}+\frac{1}{\cos \left(x\right)-1}\\\\\frac{\cos \left(x\right)-1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}+\frac{\cos \left(x\right)+1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}\\\\=\frac{\cos \left(x\right)-1+\cos \left(x\right)+1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}\\\\=\frac{2cos\left(x\right)}{cos^2\left(x\right)-1}\\\\=\frac{2cos\left(x\right)}{sin^2\left(x\right)}

=2\cdot \frac{cos\left(x\right)}{sin\left(x\right)}\cdot \frac{1}{sin\left(x\right)}\\\\=-2cot(x)csc(x)

Best Regards!

7 0
3 years ago
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