All categories

4 years ago

How are perpendicular lines and intersecting lines are alike and different

Mathematics

2 answers:

Vikki [24]4 years ago

5 0

Perpendicular lines are like a plus symbol,
but intersecting lines intersect in any way.

fenix001 [56]4 years ago

5 0

Intersecting lines cross each other like a x but they do not form any right angles but perpendicular lines cross each other like a + but they form right angles

You might be interested in

Translate this sentence into an equation.

Andrew [12]

Step-by-step explanation:

"product" means multiplication. the same as "times".

so,

135 = r×9

3 0

3 years ago

Find the value of x if x^1/12 = 121^1/24

kifflom [539]

The value is 11.

121^1/24 is actually square of 121^1/12
so x= square of 121 = 11

3 0

3 years ago

Kari lost 2.88 kilograms after two weeks of exercise. One kilogram is equal to approximately 2.2 pounds. Which measurement is cl

Andrej [43]

Answer:

Amount of weight Kari lost in pound = 6.34 pound (Approx.)

Step-by-step explanation:

Given;

Amount of weight Kari lost in kilogram = 2.88 kilograms

Given scale;

1 kilogram = 2.2 pound

Find:

Amount of weight Kari lost in pound

Computation;

Amount of weight Kari lost in pound = Amount of weight Kari lost in kilogram x 2.2 pound

Amount of weight Kari lost in pound = 2.88 x 2.2 pound

Amount of weight Kari lost in pound = 6.336

Amount of weight Kari lost in pound = 6.34 pound (Approx.)

4 0

3 years ago

Pls help me! and no files and pls actually help me

crimeas [40]

Answer:

To find m ( slope) we'll use the Slope Formula:

$\boxed{\sf{Slope\:(m)}=\cfrac{y_2-y_1}{x_2-x_1}}$

Subtract the numbers:-

$\sf 7. \:m=\cfrac{4-2}{6-5} =\boxed{2}$

_______________

$\sf 8.\: m=\cfrac{-1-3}{2-6} =\boxed{1}$

_______________

$\sf 9.\: m=\cfrac{-4-(-2)}{3-1} =\boxed{-1}$

_______________

$\sf 10.\: m=\cfrac{0-3}{0-(-3)} =\boxed{-1}$

_______________

$\sf 11.\:m=\cfrac{4-2}{3-1} =\boxed{1}$

_______________

$\sf 12.\: m=\cfrac{1-7}{2-5} =\boxed{2}$

_______________

$\sf 13.\:m=\cfrac{11-9}{1-(-4)} =\boxed{\frac{2}{5}}$

_______________

$\sf 14.\:m=\cfrac{2-3}{3-5} =\boxed{\frac{1}{2}}$

_______________

$\sf 15.\: m=\cfrac{11-5}{2-9} =\boxed{-\frac{6}{7}}$

_______________

$\sf 16.\: m=\cfrac{-7-\left(-6\right)}{8-13}=\boxed{\frac{1}{5}}$

_______________

$\sf 17.\: m=\cfrac{4-4}{6-1} =\boxed{0}$

_______________

$\sf 18. \: m=\cfrac{2-(-7)}{5-5}=$

↑ Undefined

___________________________________

6 0

3 years ago

A.ASA postulate B.SAS postulate C.SSS postulate D.AAS theorem

tester [92]

I think it’s SAS postulate .

6 0

3 years ago

Read 2 more answers