Answer:
the answer of your question is yes
Answer:
V₂ = 145.35 L
Explanation:
Given data:
Initial volume = 400 L
Initial pressure = 300 mmHg (300/760 =0.39 atm)
Initial temperature = 20 °C (20 +273 = 293 K)
Final temperature = 273 K
Final volume = ?
Final pressure = 1 atm
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂ /T₁ P₂
V₂ = 0.39 atm × 400 L × 273 K / 293 K × 1 atm
V₂ = 42588 atm.L.K /293 K.atm
V₂ = 145.35 L
"K" is Potassium. If that is the answer you are needing.
Answer : The density of an object is, 
Solution : Given,
Mass of an object = 60 g
Volume of an object = 
Formula used :
Now put all the given values in this formula, we get the density of an object.
Therefore, the density of an object is,
n=20 mol
(NH)4 SO4
Atomic masses :
N- 14
H- 1
S- 32
O- 16
Therefore M= 14×2 + 1×8 + 32 + 16×4
= 132
m= nM
= 20×132
= 2640g
