Answer:
She is likely to crash because her flight gradient is lesser than the flight gradient required gradient to avoid crashing
Explanation:
The given parameters are;
The required gradient of the plane Ashley is flying needs to reach in order to take off and not crash = 360 m/km
The initial elevation of the plane Ashley is flying = Sea level = 0 m
The goal Ashley intends to make = Elevation of 1000 m at 2.8 km. distance
∴ Ashley's goal = Traveling from sea level to 1000 m at 2.8 km horizontal distance
We have;
The gradient = Rate of change of elevation/(Horizontal distance)
Therefore;
The gradient of Ashley's flight = (1000 - 0)/(2.8 - 0) = 357.143 m/km
The gradient of Ashley's flight ≈ 357.143 m/km which is lesser than the required 360 m/km in order to take off and not crash, therefore, she will crash.
Answer:
1-An object's velocity will change if a net force acts on the object. (True)
2-In order not to slow down, a car moving at a constant velocity needs a small net force applied. (False)
3- The net force which acts on an object which remains at rest is zero. (True)
4- If an object's speed does not change, no net force is acting on the object.(True)
5- If two objects are under the influence of equal forces, they have the same acceleration. (False)
6- During the collision of a car with a large truck, the truck exerts a greater force on the car than the car exerts on the truck.(False) (Newton Third Law)
4. <span>a) TC
5. </span><span>d) place where warm air rises over cold air.
8. a) True</span>
Compared to a virtual image, a real image can be observed on a screen.
Explanation
When a beam of light meets at a specific point after the reflection from the mirror, the image formed at the point is said to be a real image.
Real images are generally inverted.
When a beam of light seems to appear to meet at a certain point after the reflection from the mirror, the image formed at the point is said to be a virtual image.
Virtual images are generally erect.
We have equation of motion v = u + at
Where v = final velocity, u = initial velocity, a = acceleration, and t = time
In this case car is travelling in -x direction
Velocity of car = displacement / time
Since displacement value is increasing in negative x axis it's initial velocity is negative
And it's final velocity is zero since it comes to rest, and time is also positive
So, v= u+ at => 0 = -u + at
So, a = u/t
Which is positive and along positive X - direction