Answer:
The distance traveled during its acceleration, d = 214.38 m
Explanation:
Given,
The object's acceleration, a = -6.8 m/s²
The initial speed of the object, u = 54 m/s
The final speed of the object, v = 0
The acceleration of the object is given by the formula,
a = (v - u) / t m/s²
∴ t = (v - u) / a
= (0 - 54) / (-6.8)
= 7.94 s
The average velocity of the object,
V = (54 + 0)/2
= 27 m/s
The displacement of the object,
d = V x t meter
= 27 x 7.94
= 214.38 m
Hence, the distance the object traveled during that acceleration is, a = 214.38 m
Answer:
Explanation:
θ
X-direction | Y-direction
⇒ 
|
Magnetic force, gravitational force, electrostatic force, frictional force.
Those are the top 4 main types of forces.
Hope this helps and hope you have a great day and brainiest is always appreciated
Work done (J) = Force (N) x Distance (m)
The Correct answer is (B), Because the reject each other.
