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dybincka [34]
3 years ago
9

A physics student tests the theory of projectile motion by leaping off a 225 meter tall building. She runs off the building hori

zontally at 12.5 m/s. How far away from the base of the building should she place the safety net?
Physics
1 answer:
tamaranim1 [39]3 years ago
4 0
In this item, we are given with the x-component of the velocity. The y-component is equal to 0 m/s. The time it takes for it to reach the volume can be related through the equation,

   d = V₀t + 0.5gt²

Substituting the known values,

  225 = (0 m/s)(t) + (0.5)(9.8)(t²)

Simplifying,
 
   t = 6.776 s

To determine the distance of the student from the edge of the building, we multiply the x-component by the calculated time.


   range = (12.5 m/s)(6.776 s)

   range = 84.7 m

<em>Answer: 84.7 m</em>

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A 477 g portion of soup is heated in a microwave oven from 25°C to 90°C, using radiation with a wavelength of 1.55 × 10⁻² m. Ass
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To solve this problem we will use the heat transfer equations, to determine the amount of heat added to the body. Subsequently, through the energy ratio given by Plank, we will calculate the energy of each of the photons. The relationship between total energy and unit energy will allow us to determine the number of photons

The mass of water in the soup is 477g

The change in temperate is

\Delta T = (90+273K)-(25+273K) = 65K

Use the following equation to calculate the heat required to raise the temperature:

q = mc\Delta T

Here,

m = Mass

c = Specific Heat

q = (477)(4.184)(65)

q = 129724.92J

The wavelength of the ration used for heating is 1.55*10^{-2}m

The number of photons required is the rate between the total energy and the energy of each proton, then

\text{Number of photons} = \frac{\text{Total Energy}}{\text{Energy of one Photon}}

This energy of the photon is given by the Planck's equation which say:

E = \frac{hc}{\lambda}

Here,

h = Plank's Constant

c = Velocity of light

\lambda = Wavelength

Replacing,

E = \frac{(6.626*10^{-34})(3*10^8)}{1.55*10^{-2}}

E = 1.28*10^{-23}J

Now replacing we have,

\text{Number of photons} = \frac{82240.7}{1.28*10^{-23}}

\text{Number of photons} = 6.41*10^{27}

Therefore the number of photons required for heating is 6.41*10^{27}

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