Question

A physics student tests the theory of projectile motion by leaping off a 225 meter tall building. She runs off the building horizontally at 12.5 m/s. How far away from the base of the building should she place the safety net?

Answer 1

In this item, we are given with the x-component of the velocity. The y-component is equal to 0 m/s. The time it takes for it to reach the volume can be related through the equation,

   d = V₀t + 0.5gt²

Substituting the known values,

  225 = (0 m/s)(t) + (0.5)(9.8)(t²)

Simplifying,
 
   t = 6.776 s

To determine the distance of the student from the edge of the building, we multiply the x-component by the calculated time.


   range = (12.5 m/s)(6.776 s)

   range = 84.7 m

Answer: 84.7 m