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cupoosta [38]
2 years ago
9

Is anyone able to answer this?

Mathematics
1 answer:
Sveta_85 [38]2 years ago
6 0

Step-by-step explanation:

(59,76) , (65,100)

independent variable 76times per minute and 100 per minute dependent variable 65°F and 59°F

m = \frac{y2 - y1}{x2 - x1}  =  \frac{100 - 76}{65 - 59}  = 4

y = mx + b

76 = 4(59)+b

b = -160

y= 4x -160

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Aleonysh [2.5K]
The solution to the system of linear equations is where the two lines intersect.

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The answer is C.
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Line HF is tangent to circle D at point E. SEgment DE is the radius of circle D, what is true about DEF?
ivolga24 [154]

When we draw a circle with the centre at D and have a tangent HF to the circle D at point E, the angle DEF will be a right angle.

In other words angle DEF = 90 degrees

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3 years ago
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Please solve with explanation (high points)
Hunter-Best [27]

Step-by-step explanation:

so, we have a large triangle made of the 2 cables as legs and the ground distance AB as baseline.

the tower is the height to the baseline of that large triangle.

let's call the top of the tower T.

and remember, the sum of all angles in a triangle is always 180°.

we know the angle A = 62°, and angle B = 72°.

assuming that AB is a truly horizontal line that means that the 2 legs (cables) have different lengths, the triangle is not isoceles, and the tower is not in the middle of the baseline.

so, the height (tower) splits the baseline into 2 parts. let's call them p and q.

p + q = 12 m

p = 12 - q

let's simply define that p is the part of the baseline on the A side, and q is the part of the baseline on the B side.

we have now 2 small right-angled triangles the large height (tower) splits the large triangle into.

one has the sides

AT, height (tower), p

angle A = 62°

angle T = 180 - 90 - 62 = 28°

the other has the sides

BT, height (tower), q

angle B = 72°

angle T = 180 - 90 - 72 = 18°

now remember the law of sine :

a/sin(A) = b/sin(B) = c/sin(C)

with the sides and the associated angles being opposite.

p/sin(28) = height/sin(62)

q/sin(18) = height/sin(72)

we know from above that

p = 12 - q

so,

(12 - q)/sin(28) = height/sin(62)

height = (12 - q)×sin(62)/sin(28)

q/sin(18) = height/sin(72)

height = q×sin(72)/sin(18)

and therefore, as height = height we get

(12 - q)×sin(62)/sin(28) = q×sin(72)/sin(18)

(12 - q)×sin(62)×sin(18) = q×sin(72)×sin(28)

12×sin(62)×sin(18) - q×sin(62)×sin(18) =

= q×sin(72)×sin(28)

12×sin(62)×sin(18) = q×sin(72)×sin(28) + q×sin(62)×sin(18) =

= q×(sin(72)×sin(28) + sin(62)×sin(18))

q = 12×sin(62)×sin(18) / (sin(72)×sin(28) + sin(62)×sin(18))

q = 4.551603755... m

p = 12 - q = 7.448396245... m

height = q×sin(72)/sin(18) = 14.00839594... m ≈ 14 m

the cell tower is about 14 m tall.

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2 years ago
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Peggy has 12 practice sessions

The first step is finding the unit rate. We can do this by evaluating

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