Hydroboration addition of borane to a compound across the double bond.
<h3>What is hydroboration?</h3>
The reaction that is called hydroboration could be carried out with an alkene or an alkyne as the case maybe. In each case, the reaction involves the addition of borane to a compound across the double bond. The reaction could further proceed to produce an alkanol.
Let us restate that like most of the organic reactions, this reaction occurs in a sequence of steps and each step of the reaction has a way of bringing us closer to the end product of the entire steps of the reaction take in proper order
As shown in the image attached to this answer, the reaction was carried out in DMS in order to stabilize the borane. We have shown the borane to be a reactant as it adds across the double bond to yield the product.
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Atoms 'like' to have 8 valence electrones. sodium has one electron 'in excess' and chlorine 'lacks' in one. so they just exchange :) both are happy. then the ionic bond is formed because chlorine is now charged negative (additional electron) and sodium is charged positive (gave up one electrone) - the opposite charges cause electrostatic pull. many atoms, many bonds and thats how salt is built.
Answer:
its 19 I'm pretty sure about
Answer:
<h3>The answer is 30 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula

From the question
mass = 60 g
volume = 2 cm³
We have

We have the final answer as
<h3>30 g/cm³</h3>
Hope this helps you