A solution of rubbing alcohol is 78.5 % (v/v isopropanol in water. how many milliliters of isopropanol are in a 90.8 ml sample o
1 answer:
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Explanation:
As the total concentration is given as 1.2 mM. And, it is also given that salt present in the solution is NaCl.
As sodium chloride is an ionic compound so, when it is added to water then it will dissociate into sodium and chlorine ions as follows.
So, it means in total there will be formation of 2 ions when one molecules of NaCl dissociates.
Therefore, concentration of chlorine ions will be calculated as follows.
Concentration of ions =
= 0.6 mM
Thus, we can conclude that the concentration of chloride ions is 0.6 mM.