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alina1380 [7]
3 years ago
8

A solution of rubbing alcohol is 78.5 % (v/v isopropanol in water. how many milliliters of isopropanol are in a 90.8 ml sample o

f the rubbing alcohol solution?
Chemistry
1 answer:
poizon [28]3 years ago
4 0
.785 x 90.8mL = 71.3 mL
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<h3>Answer:</h3>

1379.4 Joules

<h3>Explanation:</h3>
  • The quantity of heat is calculated multiplying the mass of a substance by heat capacity and the change in temperature.

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Quantity of heat = Mass × specific heat capacity × Change in temperature

Q = mcΔT

In this case;

The substance dissolved in water gained heat while water lost heat energy.

Thus, Heat gained by the substance = heat lost by water

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        = 75 g × 4.18 J/g·⁰C × 4.4 °C

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