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Maksim231197 [3]
4 years ago
9

I need help figuring out how to get this from 20 people to thirty people.

Mathematics
1 answer:
nekit [7.7K]4 years ago
7 0

Answer: you simply add an additional half of the entire recipe

Step-by-step explanation:

1/4 cup butter

2/3 cup sugar

So on so forth...

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Help geometry is very hard lol
blsea [12.9K]

Answer:

A. is your answer.

Step-by-step explanation:

If you look at the picture, you can see that S and T are congruent with each other.

LG and TD are not congruent along with L and D.

A. is your answer.

3 0
3 years ago
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
Coordinates will be fine PLs ASAP cause I need this rn<br> 13 POINTS!!!
grigory [225]

If the vertices of the triangle are J(-3,-5), K(-2,2) and L(1,-4) then its reflection in y axis are J(3,-5), K(2,2) and L(-1,-4)

Given,

The vertices of the triangle = J(-3,-5), K(-2,2) and L(1,-4)

We know,

In reflection in y axis (x,y)  will become (-x,y)

Then the vertices of the reflection in y axis = J(3,-5), K(2,2) and L(-1,-4)

Draw the triangle using the vertices.

Hence, if the vertices of the triangle are J(-3,-5), K(-2,2) and L(1,-4) then its reflection in y axis are J(3,-5), K(2,2) and L(-1,-4)

Learn more about reflection here

brainly.com/question/15487308

#SPJ1

3 0
1 year ago
9. Is the line through points P(7, 3) and Q(11, 0) perpendicular to the line through points R(6, –3) and S(3, 1)? Explain.A)Yes;
Alekssandra [29.7K]

Answer:

C) No, their slopes are not opposite reciprocals.

Step-by-step explanation:

First we find the slopes.

slope of PQ = (3 - 0)/(7 - 11) = 3/(-4) = -3/4

slope of RS = (-3 - 1)/(6 - 3) = -4/3

product of the slopes = (-3/4) * (-4/3) = 1

The slopes are reciprocals, but they are not opposite reciprocals, so the lines are not perpendicular.

7 0
4 years ago
A sixth number will be added to the list. What must it be in order for the mean to be 12?
Nataliya [291]
The sixth number should be 16 in order for the mean to be 12
7 0
3 years ago
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