Answer:
it looks decent just give it make it more detailed otherwise it looks good
B is the correct answer I think
Answer:
<h3>
♁ Question : Solve for x</h3>
<h3>♁ Step - by - step explanation</h3>
Move 12x to L.H.S ( Left Hand Side ) and change it's sign
➛
Move 7 to R.H.S ( Right Hand Side) and change it's sign
➛
Subtract 12x from 15x
Remember that only coefficients of like terms can be added or subtracted.
➛
Add the numbers : 2 and 7
➛
Divide both sides by 3
➛ 
➛ 
The value of x is 
✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄
☄ Now, let's check whether the value of x is 3 or not!
<h3>
☥ Verification :</h3>
L.H.S = R.H.S ( Hence , the value of x is 3 ).
✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄
<h3>✒ Rules for solving an equation :</h3>
- If an equation contains fractions ,multiply each term by the L.C.M of denominators.
- Remove the brackets , if any.
- Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
- Simplify and get the single term on each side.
- Divide each side by the coefficient of variable and then get the value of variable.
Hope I helped!
Have a wonderful time ! ツ
~TheAnimeGirl
Answer:
Definitions:
The third quartile, denoted by Q3 , is the median of the upper half of the data set. This means that about 75% of the numbers in the data set lie below Q3 and about 25% lie above Q3;
The upper half of a data set is the set of all values that are to the right of the median value when the data has been put into increasing order;
First, we verify data in increasing order:
21, 24, 25, 28, 29, 35, 37, 38, 42 ( okay);
The median is 29;
Therefore, the upper half of the data is {35, 37, 39, 42};
Q3 = ( 37 + 39 ) / 2 = 76 / 2 = 38;
Step-by-step explanation:
Step-by-step explanation:
Sn= a+[n-1]d
S2= a+[2-1]d
8.5 = a+d _______Equation 1
S5 = a+[5-1]d
13=a+4d ________Equation 2
Subtract Equation 1 from Equation 2
13=a+4d
-
8.5= a+d
________
4.5= 3d
d=1.5
Substituting d=1.5 in equation 1
8.5=a+1.5
a=8.5-1.5
a=7
Sum of terms of an A.P =
Sn= n/2[2a+(n-1)d]
292= n/2[2×7+(n-1)d]
292=n/2[14+(n-1)1.5
292×2=n[14+(n-1)1.5]
584=n[14+1.5n-1.5]
584= 14n+1.5n²-1.5n
584= 1.5n²+12.5n
1.5n²+12.5n-584
1.5n²-24n+36.5n-584
1.5n(n-16)+36.5(n-16)
(1.5n+36.5)(n-16)
**n-16=0
n=16
