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xz_007 [3.2K]
3 years ago
14

An empty 230 kg elevator accelerates upward

Physics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

7.2 as used in the equation

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A car traveling at 45 miles per hour is brought to a stop, at constant deceleration, 132 feet from where the brakes are applied.
Nataliya [291]

Answer:

c

Explanation:

4 0
3 years ago
Consider a railroad bridge over a highway. A train passing over the bridge dislodges a loose bolt from the bridge, which proceed
schepotkina [342]

Answer:

12.35m

Explanation:

Hello! To solve this problem we must consider the following:

1. The car moves with constant speed, which means that the distance traveled is equal to the multiplication of time by speed.

X = VT

we solve the equation for time

T=\frac{x}{V} =\frac{27}{17} =1.588s

2. The bolt moves with constant acceleration, with acceleration of 9.81m / s ^ 2, so we could apply the following equation.

note=remember that "a uniformly accelerated motion", means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

Y= VoT-\frac{1}{2}gt^{2}

where

Vo = Initial speed

=0

T = time

=1.588s

g =gravity=9.8m/s^2

Y =  bridge height

solving

Y= \frac{1}{2}gt^{2}\\Y=(0.5)(9.8)(1.588^2)=12.35m

4 0
3 years ago
14233334124211241234
Kryger [21]

Answer:

Excuse me what? Or is that the question

3 0
3 years ago
Why does air near the equator rise
Vesnalui [34]
Because it’s warmer and more humid
8 0
3 years ago
A tourist wishes to catch a train in 1.2 hours, which is 115 km away. If she spends the first half-hour going 90km/h, how fast w
lakkis [162]

Answer:

100km/hr

Explanation:

From the problem statement we know that distance of the trip is 115km

Expected time for the trip = 1.2hrs

→ If she spends the first half-hour going 90km/hr,

    Here  time  = 0.5hr

              speed  = 90km/hr

 The distance covered;

    Distance covered   =  Speed x time

    Distance covered  = 90 x 0.5  = 45km

→The remaining distance will be:

        Total distance - distance covered

              115km  - 45km  = 70km

→ The remaining time;

      1.2hr - 0.5hr  = 0.7hr

 Speed  = \frac{distance}{time}  

  Insert the parameters and solve;

  Speed  = \frac{70}{0.7}   = 100km/hr

For the remaining lap, the tourist must travel at a rate of 100km/hr to catch up.

4 0
3 years ago
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