Use the equation for the acceleration
A = final velocity - initial velocity divided by time final - time initial
A= 54 - 32 / 8 - 0
A= 22 / 8
A= 2.75 m/s^2
Hope this helps!
Answer:
So after stretching new resistance will be 0.1823 ohm
Explanation:
We have given initially length of the wire 
Radius of the wire 
Resistance of the wire initially 
We know that resistance is equal to
,here
is resistivity, l is length and A is area
From the relation we can say that 
Now length of wire become 6.75 m
Volume will be constant
So 
So 

So 

1. a=(v-v0)/t
a=14 m/s / 2s
a=7 m/s^2
2. <span>a=(v-v0)/t
</span>a=(30 m/s - 0 m/s) / 12 s
a=2.5 m/s^2
3. <span>a=(v-v0)/t
a=(37 m/s - 22 m/s) / 2 s
a= 7.5 m/s^2
4. </span><span>a=(v-v0)/t
a=(12 km/s - 0 km/s)/8 s
a=1.5 km/s^2
etc</span>
The answer should be false because it doesnt say if the car is traveling at constant speed. The cars speed can be various so that in total for 2 hours that it travels it passes 80 miles. If however it actually traveled at constant speed than the answer is true.