Orient the semi-circle arc such that it is symmetric with respect to the y-axis. Now, by symmetry, the electric field in the x-direction cancels to zero. So the only thing of interest is the electric field in the y-direction.
dEy=kp/r^2*sin(a) where k is coulombs constant p is the charge density r is the radius of the arc and a is the angular position of each point on the arc (ranging from 0 to pi. Integrating this renders 2kq/(pi*r^3). Where k is 9*10^9, q is 9.8 uC r is .093 m
I answeared your question can you answear my question pleas
Answer:
5.08*10^{-13}N
Explanation:
With this information we can calculate the velocity of the proton by taking into account the kinetic energy of the proton:

The magnitude of the magnetic force will be:

hope this helps!
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Hope this helped! i’m not sure if it’s right. it honestly bored so i’m answering questions.