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Leni [432]
3 years ago
12

2 hr 20 min to 40 min

Mathematics
2 answers:
lidiya [134]3 years ago
4 0
100 minutes bc 2hr and 20 min is 140 minutes and 40 -140 is 100
weqwewe [10]3 years ago
3 0

Answer:

what do you mean?

Step-by-step explanation:

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PLEASE HELP ASAP
Katyanochek1 [597]

m = 5 and n = 3

let f(x) = 2x³ - mx² + nx - 2 , then

f( - 1 ) = - 2 - m - n - 2 = - 12

f(2 ) = 16 - 4m + 2n - 2 = 0

Tidying up the 2 equations

- m - n = - 8 → (1)

- 4m + 2n = - 14 → ( 2)

multiply equation ( 1) by 2

- 2m - 2n = - 16 → ( 3 )

add ( 2 ) and ( 3 ) term by term

-6m = - 30 ⇒ m = 5 ( substitute m = 5 into (2 )

- 20 + 2n = - 14

2n = 6 ⇒ n = 3



5 0
3 years ago
Read 2 more answers
The length of a planet's orbit around a star is approximately 29,870,000 km.
Sliva [168]

Answer:

745 k/hr

Step-by-step explanation:

mathematically, 1 day = 24 hours

1670 days = 1670 * 24 = 40,080 hours

The speed is thus;

(29,870,000)/40,080 = 745.259

= 745 km/h

5 0
2 years ago
What is the median for 252,210,264,278,208,295,248,257,284,271....expressed to the nearest tenth.
babymother [125]

Answer:

260.5

Step-by-step explanation:

7 0
3 years ago
Help quickly plsss<br><br><br><br><br> Hsjsjdjjd
I am Lyosha [343]

Answer:

answer is 75

Step-by-step explanation:

6÷8x100=75%

from 58 to 66 its have 6 colums..thats why 6/8

5 0
3 years ago
Identify whether the function graphed has an odd or even degree and a positive or negative leading coefficient.
Shtirlitz [24]

Answer:

odd degree and positive leading coefficient

Step-by-step explanation:

From the graph , we can see that when x goes to infinity , y goes to infinity

As x--> ∞, y--> ∞ (As x increases the value of y increases on the positive side)

we can see that when x goes to -infinity , y goes to -infinity

As x--> -∞, y--> -∞ (As x decreases the value of y decreases on the negative side)

When x--> ∞, y--> ∞   and x--> -∞, y--> -∞

The leading coefficient is positive  and largest exponent is odd

So the graph has odd degree and positive leading coefficient


8 0
2 years ago
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