To Find :
How many gallons of a 80% antifreeze solution must be mixed with 100 gallons of 20% antifreeze to get a mixture that is 70% antifreeze.
Solution :
Let, x gallons of 80% antifreeze solution is required :
So,

Therefore, 500 gallons of 80% antifreeze solution is required.
Answer:
198
Step-by-step explanation:
2+6=8+10=18+14=32+18=50+22=72+26=96+30=126+34=160+38=198
Answer:
not enough info
Step-by-step explanation:
Answer:
x = 4 or x = -4
Step-by-step explanation:
Answer:
V = Bh
Step-by-step explanation: